Which therapy is NOT based on classical conditioning?

can somebody plsss help me answer all these this is whats holding me back from passing and i would appreciate it if you are will

pishuonlain [190]

13 is the 3rd one
17 is the 2nd one
18is the 3rd one
24 is the 3rd one.
Hope this helps!

7 0

3 years ago

In the 18th, 19th, and early 20th centuries, a wide variety of resistance movements across Asia and Africa fought against Europe

frutty [35]

Answer:

India's independence movement and revolts in Sudan.

Explanation:

These two campaigns are fought in all factors. The riots in Sudan were triggered by religion and brought out by violent processes. France had authority in Sudan, and the organizers of the faith-sponsored campaign attempted to overcome French rule. On the other hand, the old Indian freedom movement was not on a violent pathway. Civil disobedience, nonviolent protests were the main techniques of resistance. India's independence campaign is promoted by ethnicity and nationalism. So one campaign used violent and militant ways, while the other campaign used revolution and patriotism.

8 0

2 years ago

1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The

Arlecino [84]

Hi there!

a.

To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.

$\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt$

Evaluate using a calculator:

$= 899.97 \approx \boxed{900\text{ people}}$

b.

To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.

In other terms:
$\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt$

We can evaluate using a calculator (math-9 on T1-84):

$\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt$

$= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}$

c.

If:
$P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt$

Then:

$\frac{dP}{dt} = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt = S(t) - R(t)$

Evaluate at t = 20:

$S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669$

$S(20) - R(20) = 87.844 - 108.669 = -20.823$

This means that at t = 20, there is a <u>NET DECREASE</u> of people at the movie theater of around 20.823 (21) people per hour.

d.

To find the maximum, we must use the first-derivative test.

Set S(t) - R(t) equal to 0:

$80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0$

Graph the function with a graphing calculator and set the function equal to y = 0:

According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.

<u>Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.</u>

8 0

2 years ago

if you need any advice with anything, let me know. I will put my social medias in the comments. it can be about anything:) but p

Llana [10]

Answer:

I don't think so I am need of advice or in difficulty now

Explanation:

if anytime I need advice, would ask you

7 0

3 years ago

True or false

juin [17]

True i do believe but im not 100% sure this isnt my strong suite

8 0

3 years ago

Read 2 more answers