Solving for the missing term and the missing coefficient (6a − )5a = ( ) a^2 − 35a
Let the missing term be X
Let the missing coefficient be Y
Therefore, (6a – X)5a = Y(a^2) – 35a
6a x 5a – X.5a = Y.a^2 – 35a
30a^2 – X.5a = Y.a^2 – 35a
Equating co-efficients,
30a^2 = Y.a^2; X.5a = 35a
30 = Y; 5X = 35
Y = 30; X = 7
Therefore, (6a-7)5a = 30 a^2 – 35a
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Answer:
Not in the right time
Step-by-step explanation:
ana is the root of before and chronous=krounus, being the Greek word for time.
Let, the angles = a, b
It is given that, a+b /5 = 24
a + b = 120 --- equation (1)
a-b/2 = 14
a - b = 28 ---- equation (2)
a = 28 + b
Now, substitute this value of b in equation (1),
28 + b + b = 120
2b = 120 - 28
b = 92/2
b = 46
Now, a = 28 + b = 28 + 46 = 74
In short, Your Angles are 74 and 46
Hope this helps!
Answer:
0
Step-by-step explanation:
