How would you solve 3/4 over 1/2 as a ratio

Mathematics

1 answer:

miskamm [114]3 years ago

6 0

Answer:

3/2

Step-by-step explanation:

A couple of different methods are used for dividing fractions.

1. "Invert and multiply". Dividing by a number is the same as multiplying by its reciprocal:

(3/4) / (1/2) = (3/4) × (2/1)

= (3·2)/(4·1) = 6/4 = 3/2

2. Make the denominators the same and use the ratio of numerators.

(3/4) / (1/2) = (3/4) / (2/4) = 3/2

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For these fractions, you can recognize that 3/4 is 1/4 more than 1/2, and that 1/4 is half of 1/2. That means 3/4 is half-again as much as 1/2, so is 1 1/2 = 3/2 times 1/2. This tells you the ratio (3/4) : (1/2) = 3/2.

Along the lines of the above, you can write the ratio as ...

(3/4) : (1/2)

and multiply by 4 to get

= (3/4)×4 : (1/2)×4 = 3 : 2

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in a proportional relationship the ratio y/x is constant. Show that this ratio is not constant for the equation y=a-14

Colt1911 [192]

To show that the ratio $\frac{y}{x}$ is not constant for the function $y=a-14$ we only need to evaluate this function at 2 points and then show that the ratio is not the same for those two points. Note that here $a$ represents $x$ .

To find the counter examples here, I will use the values $a=20$ and $a=28$ . For $a = 20$ , the equation tells us that the output is

$y=20-14=6$ . For this value of $a$ the point is point is $(20,6)$ . The ratio $\frac{y}{x} =\frac{6}{20}$ . For the $a=28$ , $y=28-14=14$ . For this value of $a$ the point is $(28,14)$ . The ratio $\frac{y}{x} =\frac{14}{28} =\frac{1}{2}$ . Clearly this ratio is not constant for all ordered pairs.