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Anna [14]
2 years ago
10

Describe the domain and range of y = 2(4)x+ ³ +2.

Mathematics
1 answer:
sp2606 [1]2 years ago
6 0

Answer:

=13 era muy fácil yo lo hice mentalmente

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X^2-5x+2 x 3x^2 +2x +3
Katen [24]

Answer:

3x^4 - 13x^3 - x^2 - 11x + 6.

Step-by-step explanation:

x^2-5x+2 x 3x^2 +2x +3

= x^2(3x^2 +2x +3)  - 5x(3x^2 +2x +3) + 2(3x^2 +2x +3)

=  3x^4 + 2x^3 + 3x^2 - 15x^3 - 10x^2 - 15x + 6x^2 + 4x + 6

Adding like terms:

= 3x^4 - 13x^3 - x^2 - 11x + 6.

5 0
3 years ago
Help PLZZZZZZZ:)))))
Scilla [17]
The answer is D. First add 2k, then divide by a, the subtract x, then divide by -1
4 0
3 years ago
I need help with this question
k0ka [10]
F(x) = 1 / (x - 2)...when x = 4
f(4) = 1 / (4 - 2)
f(4) = 1/2 <==

f(x) = 1 / (x - 2)...when f(x) = 1
1 = 1 / (x - 2) ...multiply both sides by (x - 2) eliminating it on the right
1(x - 2) = 1
x - 2 = 1
x = 1 + 2
x = 3 <==
8 0
3 years ago
Read 2 more answers
Sally has saved one thousand five hundred cents over nine days from selling lemonade how many dollars does sally have?
KonstantinChe [14]

Answer:

she has saved $5 in the last 9 days because she has saved 500 cents the last 9 days there are 100 cents in a dollar which means she has to save $5

5 0
3 years ago
each of the 20 balls is tossed independently and at random into one of the 5 bins. let p be the probability that some bin ends u
amm1812

if p is the probability that some bin ends up with 3 balls and q is the probability that every bin ends up with 4 balls. pq is 16.

First, let us label the bins with 1,2,3,4,5.

Applying multinomial distribution with parameters  n=20  and  p1=p2=p3=p4=p5=15  we find that probability that bin1 ends up with 3, bin2 with 5 and bin3, bin4 and bin5 with 4 balls equals:

5−2020!3!5!4!4!4!

But of course, there are more possibilities for the same division  (3,5,4,4,4)  and to get the probability that one of the bins contains 3, another 5, et cetera we must multiply with the number of quintuples that has one 3, one 5, and three 4's. This leads to the following:

p=20×5−2020!3!5!4!4!4!

In a similar way we find:

q=1×5−2020!4!4!4!4!4!

So:

pq=20×4!4!4!4!4!3!5!4!4!4!=20×45=16

thus, pq = 16.

To learn more about Probability visit: brainly.com/question/29508225

#SPJ4

7 0
1 year ago
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