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Anuta_ua [19.1K]
3 years ago
7

give the most general solutions to equations. . 2sinxcosx-sin(2x)cos(2x)=0. . A. simplify the first expression using double angl

e identity for sine.. B. factor the left side of equatioin. C. solve the factored equation
Mathematics
1 answer:
Zinaida [17]3 years ago
5 0
2sinxcosx - sin(2x)cos(2x) = 0 

<span>Part I </span>
<span>The double angle identity for sine states that sin(2x) = 2sinxcosx </span>
<span>Thus we get: </span>
<span>sin(2x) - sin(2x)cos(2x) = 0 </span>

<span>Part II </span>
<span>sin(2x)(1 - cos(2x)) = 0 </span>

<span>Part III </span>
<span>Either sin(2x) = 0 or </span>
<span>1 - cos(2x) = 0 </span>
<span>=> cos(2x) = 1 </span>

<span>For sin(2x) = 0, this is true for </span>
<span>2x = n(pi) where n = 0, 1, 2, .... </span>
<span>x = n(pi/2) </span>

<span>For cos(2x) = 1, this is true for </span>
<span>2x = n(pi) where n = 0, 2, 4, .... </span>
<span>x = n(pi/2)
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
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