Drag the points to create two different cylinders with the

Please choose the option that would best fit the empty space above: Group of answer choices only one optimal solution multiple o

Scrat [10]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

In this question, some of the data is missing, that's why this question can be defined as follows:

It Includes an objective feature coefficient, its sensitivity ratio is the ratio for values on which the current ideal approach will remain optimal.

When there is Just one perfect solution(optimal solution) then the equation is:

$Max \ Z = \$ 5x_1 + \$10x_2\\\\Subject\ to: \\\\8x_1 + 5x_2 \leq 80\\\\2x_1 + 1x_2 \leq 100\\\\x1, x2 \geq 0$

When there are Several perfect solutions then the equation is:

$Max \ Z = \$ \ 200x_1 + \$ \ 100x_2\\\\ Subject \ to:\\\\8x_1 + 5x_2 \leq 80\\\\2x_1 + 1x_2 \leq 100\\\\x1, x2 \geq 0$

When there is also no solution, since it is unlikely then the equation is:

$Max \ Z = \$40x_1 + \$10x_2 \\\\Subject \ to:\\\\8x_1 + 5x_2 \leq 80\\\\2x_1 + 1x_2 \geq 100\\\\x_1, x_2 \geq 0$

When there is no best solution since it is unbounded then the equation is:

$Max \ Z = \$ 30x_1 + \$15x_2 \\\\Subject to:\\\\8x_1 + 5x_2 \geq 80\\\\2x_1 + 1x_2 \geq 100\\\\x_1, x_2 \geq 0\\$

6 0

3 years ago

Simplify x+2/x^2+2x-3 divide by x+2/x^2-x

ira [324]

$\dfrac{\frac{x+2}{x^2+2x-3}}{\frac{x+2}{x^2-x}}$

If $x\neq-2$ , then we can immediately cancel the factors of $x+2$ :

$\dfrac{\frac1{x^2+2x-3}}{\frac1{x^2-x}}=\dfrac{x^2-x}{x^2+2x-3}$

Factorize the numerator and denominator:

$x^2-x=x(x-1)$

$x^2+2x-3=(x+3)(x-1)$

Next, if $x\neq1$ , then

$\dfrac{x^2-x}{x^2+2x-3}=\dfrac{x(x-1)}{(x+3)(x-1)}=\dfrac x{x+3}$

8 0

3 years ago

Helpppp big brains am I right??

noname [10]

Answer:

y=3x+4

Step-by-step explanation:

This is the correct answer

7 0

2 years ago

What is the value of x in the solution to the system of equations below?

Paraphin [41]

I’m pretty sure the answer is D. 1/3

7 0

3 years ago

Read 2 more answers

Assume that the paired data came from a population that is normally distributed. using a 0.05 significance level and dequalsxmin

Artemon [7]

"Assume that the paired data came from a population that is normally distributed. Using a 0.05 significance level and d = (x - y), find $\bar{d}$ , $s_{d}$ , the t-test statistic, and the critical values to test the claim that $\mu_{d} = 0$ "

You did not attach the data, therefore I can give you the general explanation on how to find the values required and an example of a random paired data.

For the example, please refer to the attached picture.

A) Find $\bar{d}$
You are asked to find the mean difference between the two variables, which is given by the formula:
$\bar{d} = \frac{\sum (x - y)}{n}$

These are the steps to follow:
1) compute for each pair the difference d = (x - y)
2) sum all the differences
3) divide the sum by the number of pairs (n)

In our example:
 $\bar{d} = \frac{6}{8} = 0.75$ 

B) Find $s_{d}$
You are asked to find the standard deviation, which is given by the formula:
 $s_{d} = \sqrt{ \frac{\sum(d - \bar{d}) }{n-1} }$

These are the steps to follow:
1) Subtract the mean difference from each pair's difference
2) square the differences found
3) sum the squares
4) divide by the degree of freedom DF = n - 1

In our example:
$s_{d} = \sqrt{ \frac{101.5}{8-1} }$
= √14.5
= 3.81

C) Find the t-test statistic.
You are asked to calculate the t-value for your statistics, which is given by the formula:
$t = \frac{(\bar{x} - \bar{y}) - \mu_{d} }{SE}$

where SE = standard error is given by the formula:
$SE = \frac{ s_{d} }{ \sqrt{n} }$

These are the steps to follow:
1) calculate the standard error (divide the standard deviation by the number of pairs)
2) calculate the mean value of x (sum all the values of x and then divide by the number of pairs)
3) calculate the mean value of y (sum all the values of y and then divide by the number of pairs)
4) subtract the mean y value from the mean x value
5) from this difference, subtract $\mu_{d}$
6) divide by the standard error

In our example:
SE = 3.81 / √8
= 1.346

The problem gives us $\mu_{d} = 0$ , therefore:
t = [(9.75 - 9) - 0] / 1.346
= 0.56

D) Find $t_{\alpha / 2}$
You are asked to find what is the t-value for a 0.05 significance level.

In order to do so, you need to look at a t-table distribution for DF = 7 and A = 0.05 (see second picture attached).

We find $t_{\alpha / 2} = 1.895$ 

Since our t-value is less than $t_{\alpha / 2}$ we can reject our null hypothesis!!

7 0

4 years ago