The roots of the polynomial <span><span>x^3 </span>− 2<span>x^2 </span>− 4x + 2</span> are:
<span><span>x1 </span>= 0.42801</span>
<span><span>x2 </span>= −1.51414</span>
<span><span>x3 </span>= 3.08613</span>
x1 and x2 are in the desired interval [-2, 2]
f'(x) = 3x^2 - 4x - 4
so we have:
3x^2 - 4x - 4 = 0
<span>x = ( 4 +- </span><span>√(16 + 48) </span>)/6
x_1 = -4/6 = -0.66
x_ 2 = 2
According to Rolle's theorem, we have one point in between:
x1 = 0.42801 and x2 = −1.51414
where f'(x) = 0, and that is <span>x_1 = -0.66</span>
so we see that Rolle's theorem holds in our function.
Answer:
y =
x
Step-by-step explanation:
slope-intercept form: y = mx + b
Given: slope(m) =
, point (4, -3)
We already have the value of m, but we need to find the value of b. To do this, input the given values of the slope and the point into the equation:
-3 =
(4) + b
Solve for b:
-3 =
(4) + b
-3 = -3 + b
0 = b
The value of b is zero. We can now write the equation:
y =
x + 0
y =
x
The equation written in slope-intercept form is: y =
x
Answer:
(1,K) hope i could help
Step-by-step explanation:
Answer is 2 (answer choice a)
Answer:
The LCD denominator is 1
Step-by-step explanation: