1. The time taken for the water to fall that much is 0.2 s
2. The initial speed of the water is 4 m/s
<h3>1. How to determine the time </h3>
- Height (h) = 20 cm = 20 / 100 = 0.2 m
- Acceleration due to gravity (g) = 9.8 m/s²
- Time (t) =?
h = ½gt²
0.2 = ½ × 9.8 × t²
0.2 = 4.9 × t²
Divide both side by 4.9
t² = 0.2 / 4.9
Take the square root of both side
t = √(0.2 / 4.9)
t = 0.2 s
<h3>2. How to determine the initial speed</h3>
- Horizontal distance (s) = 80 cm = 80 / 100 = 0.8 m
- Time (t) = 0.2 s
- Initial speed (u) =?
s = ut
Divide both sides by t
u = s / t
u = 0.8 / 0.2
u = 4 m/s
Learn more about motion under gravity:
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Answer:
no
Step-by-step explanation:
Answer: One of the ways you can do all this is by zearn or by listening by your teacher.
Answer:
RS = - 7
ST = - 13.5 = - 13½
RT = - 20.5 = - 20½
Step-by-step explanation:
From the question given above, the following were obtained:
RS = 6y + 2
ST = 15y + 9
RT = 5y - 13
To obtain RS, ST and RT, we must first obtain the value of y. This can be obtained as follow:
From diagram above, it is evident that:
RT = RS + ST
RS = 6y + 2
ST = 15y + 9
RT = 5y - 13
5y - 13 = 6y + 2 + 15y + 9
5y - 13 = 6y + 15y + 2 + 9
5y - 13 = 21y + 11
Collect like terms
5y - 12y = 11 + 13
- 16y = 24
Divide both side by - 16
y = 24/ - 16
y = - 1.5
Finally, we shall determine RS, ST and RT as follow:
RS = 6y + 2
y = - 1.5
RS = 6(-1.5) + 2
RS = - 9 + 2
RS = - 7
ST = 15y + 9
y = - 1.5
ST = 15(-1.5) + 9
ST = - 22.5 + 9
ST = - 13.5 = - 13½
RT = 5y - 13
y = - 1.5
RT = 5(-1.5) - 13
RT = - 7.5 - 13
RT = - 20.5 = - 20½
