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3 years ago

If ABC and EDC are similar, what is the value of x? A

Mathematics

1 answer:

abruzzese [7]3 years ago

3 0

Answer:

x = 15

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

BC/DC = EC/AC , substitute values

3x×5/32 - 5x-5/56 ( cross- multiply )

56(3x - 5) = 32(5x - 5) ← distribute and simplify both sides

168x - 280 = 160x - 160 ( subtract 160x from both sides )

8x - 280 = - 160 ( add 280 to both sides )

8x = 120 ( divide both sides by 8 )

x = 15

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The equation of a line in this form y- y1=m (x - x1) is called the point slope form.

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3 years ago

How many models of 100 do you need to model 3200 explain

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3 years ago

Read 2 more answers

Suppose that an airline quotes a flight time of 128 minutes between two cities. Furthermore, suppose that historical flight reco

ANTONII [103]

Answer:

(a) The probability density function of X is:

$f_{X}(x)=\frac{1}{b-a};\ a$

(b) The value of P (129 ≤ X ≤ 146) is 0.3462.

(c) The probability that a randomly selected flight between the two cities will be at least 3 minutes late is 0.4327.

Step-by-step explanation:

The random variable X is defined as the flight time between the two cities.

Since the random variable X denotes time interval, the random variable X is continuous.

(a)

The random variable X is Uniformly distributed with parameters a = 10 minutes and b = 154 minutes.

The probability density function of X is:

$f_{X}(x)=\frac{1}{b-a};\ a$

(b)

Compute the value of P (129 ≤ X ≤ 146) as follows:

Apply continuity correction:

P (129 ≤ X ≤ 146) = P (129 - 0.50 < X < 146 + 0.50)

= P (128.50 < X < 146.50)

$=\int\limits^{146.50}_{128.50} {\frac{1}{154-102}} \, dx$

$=\frac{1}{52}\times \int\limits^{146.50}_{128.50} {1} \, dx$

$=\frac{1}{52}\times (146.50-128.50)$

$=0.3462$

Thus, the value of P (129 ≤ X ≤ 146) is 0.3462.

(c)

It is provided that a randomly selected flight between the two cities will be at least 3 minutes late, i.e. X ≥ 128 + 3 = 131.

Compute the value of P (X ≥ 131) as follows:

Apply continuity correction:

P (X ≥ 131) = P (X > 131 + 0.50)

= P (X > 131.50)

$=\int\limits^{154}_{131.50} {\frac{1}{154-102}} \, dx$

$=\frac{1}{52}\times \int\limits^{154}_{131.50} {1} \, dx$

$=\frac{1}{52}\times (154-131.50)$

$=0.4327$

Thus, the probability that a randomly selected flight between the two cities will be at least 3 minutes late is 0.4327.

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3 years ago

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erma4kov [3.2K]

Answer:

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I don't know if it's right

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