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slava [35]
4 years ago
8

An ideal vapor-compression refrigeration cycle that uses refrigerant-134a as its working fluid maintains a condenser at 800 kpa

and the evaporator at -12 degrees
c. if the cooling load is 150 kw, determine the cop and the power required for this service in kw.

Physics
2 answers:
AlladinOne [14]4 years ago
7 0

Answer:

P= 30.87 kw

Explanation:

find the solution below

aleksandrvk [35]4 years ago
5 0

Answer:

cop = 4.859

power = 30.87 KW

Explanation:

the pictures attached herewith shows the calculation

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A beam of light in air is incident at an angle of 30º to the surface of a rectangular block of clear plastic (n = 1.46). The lig
Aneli [31]

Answer:

θ = 30°

Explanation:

Firts, the angle when the beam of light passes through the block cam be calculated using Snell Law:

n_{1}sin(\theta_{1}) = n_{2}sin(\theeta_{2})

<u>Where</u>:

n₁: is the index of refraction of the incident medium (air) = 1

θ₁: is the incident angle = 30°

n₂: is the medium 2 (plastic) = 1.46

θ₂: is the transmission angle

Hence, θ₂ is:

sin(\theta_{2}) = \frac{n_{1}*sin(\theta_{1})}{n_{2}} = \frac{1*sin(30)}{1.46} = 0.34 \rightarrow \theta_{2} = 20.03 ^{\circ}

Now, when the beam of light re-emerges from the opposite side, we have:

n₁: is the index of refraction of the incident medium (plastic) = 1.46  

θ₁: is the incident angle = 20.03°                

n₂: is the medium 2 (air) = 1

θ₂: is the transmission angle

Hence, the angle to the normal to that surface (θ₂) is:

sin(\theta_{2}) = \frac{n_{1}*sin(\theta_{1})}{n_{2}} = \frac{1.46*sin(20.03)}{1} = 0.50 \rightarrow \theta_{2} = 30 ^{\circ}  

 

Therefore, we have that the beam of light will come out at the same angle of when it went in, since, it goes from air and enters to a plastic medium and then enters again in this medium to go out to air again. This was proved using the Snell Law.    

I hope it helps you!                

5 0
3 years ago
A cannonball is shot from the top of
Komok [63]
It might be 144.2 m but i’m not for sure:)
8 0
3 years ago
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An automobile traveling 95 km/h overtakes a 1.30-km-long train traveling in the same direction on a track parallel to the road.
SCORPION-xisa [38]

Answer: 6.175 km

Explanation:

from the question, we have the following

velocity of the automobile = 95 km/g

velocity of the train = 75 km/h

length of the train = 1.30 km

since the automobile and the train are moving in the same direction, we need to find the velocity of the car relative to the train which will be their difference in speed = 95 - 75 = 20 km/h

we need to find the time it takes the automobile to overtake the train using the formula time = distance / speed , with the distance being the length of the train.

time (t) = 1.3 / 20

= 0.065 hour

now we can find the distance traveled by the automobile using the the time taken for it to overtake the train and the speed of the automobile.

therefore, distance = speed x time

     distance = 95 x 0.065 =6.175 km

5 0
4 years ago
What color does the star alpha centauri appear to be?
myrzilka [38]
B.yellow-white is the answer.
3 0
3 years ago
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Which way does the friction arrow go in a free body diagram for a moving object point
True [87]

Answer:

Frictional force opposes relative motion between surfaces

Explanation:

Friction that exists when the object is not moving is called static friction.  In static friction ,If we are applying a force in the object the frictional force is in the opposite  direction . If it is not the case, there have been some net force and the object starts accelarating.

The main component of the contact force of two objects is normal force and that is in the perpendicular direction.  Frictional force is other complnent. This frictional force is parallel to the interface between objects. Frictional force opposes relative motion between surfaces.

7 0
4 years ago
Read 2 more answers
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