Answer:
The speed of transverse waves in this string is 519.61 m/s.
Explanation:
Given that,
Mass per unit length = 5.00 g/m
Tension = 1350 N
We need to calculate the speed of transverse waves in this string
Using formula of speed of the transverse waves
Where, 
= mass per unit length
T = tension
Put the value into the formula
Hence, The speed of transverse waves in this string is 519.61 m/s.
No. I do not agree with Stefan. Quite the contrary. I disagree
with his description of "<span>angle of incidence" as the angle between
the surface of the mirror and the incoming ray.
The correct description of "angle of incidence" is </span><span>the angle between
the NORMAL TO the surface of the mirror and the incoming ray.
Thus, the true angle of incidence is the complement of the angle that
Stefan calculates or measures.</span>
Answer:
The best time to view the spectacle on Dec. 21 will be around an hour after sunset.
Answer:
a) 20 nodes b) zero nodes
Explanation:
When we have standing waves in a bend we have nodes at the ends and the equation describes the number of possible waves in the string is
L = n λ/2
Where λ is the wavelength, L is the length of the string, in our case it would be D and n is an entered. We can strip the wavelength of this expression
λ = 2L / n
Let's calculate what value of n we have for a wavelength equal to D/10
λ = 2D / n
λ = D / 10
We match and calculate
2D / n = D / 10
2 / n = 1/10
n = 20
Perform them for λ = D / 20
λ = 2D / n
2D / n = D / 20
n = 2 20 = 40
Since n is an inter there should be a wavelength for each value of n in the bone period there should be 20 different wavelengths
B) for La = 10D
2D / n = 10D
1 / n = 5
n = 1/5 = 0.2
La = 20D
2D / n = 20D
1 / n = 10
n = 1/10 = 0.1
These numbers are not entered so there can be no wave in this period
