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3 years ago

How much is the tension number 2

Physics

1 answer:

mestny [16]3 years ago

4 0

This is what I got:

Net force in the Y direction:

ΣFy = T1 - T2

F = ma

ma = T1 - T2

Isolate for T2

ma - T1 = -T2

Multiply by -1

T1 - ma = T2

100 - (3)(2) = T2

100 - 6 = T2

T2 = 94 N

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Soloha48 [4]

Answer:

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$\boxed{\sf Distance \ covered \ (s) = 100 \ m}$

Given:

Initial velocity (u) = 0 m/s

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To Find:

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(ii) Distance covered (s)

Explanation:

$\sf (i) \ From \ 1^{st} \ equation \ of \ motion:$

$\sf \implies v = u + at$

$\sf \implies 20 = 0 + a(10)$

$\sf \implies 10a = 20$

$\sf \implies \frac{10a}{10} = \frac{20}{10}$

$\sf \implies a = 2 \: m/ {s}^{2}$

$\sf (ii) \ From \ 2^{nd} \ equation \ of \ motion:$

$\sf \implies s = ut + \frac{1}{2} a {t}^{2}$

$\sf \implies s = (0)(10) + \frac{1}{2} \times 2 \times {(10)}^{2}$

$\sf \implies s = \frac{1}{ \cancel{2}} \times \cancel{2} \times {(10)}^{2}$

$\sf \implies s = {10}^{2}$

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