To find the horizontal distance multiple the horizontal velocity by the time. Since there is no given time it must be calculated using kinematic equation.
Y=Yo+Voyt+1/2at^2
0=.55+0+1/2(-9.8)t^2
-.55=-4.9t^2
sqrt(.55/4.9)=t
t=0.335 seconds
Horizontal distance
=0.335s*1.2m/s
=0.402 meters
Answer:
Explanation:
Hello! To solve this problem we must be clear about the concept of energy conservation, and kinetic energy with the following sentence
The kinetic energy of the two cars (v = 1.2m / S) plus the kinetic energy of the third car (v = 3.5m / S) must be equal to the kinetic energy of the three cars together.
The kinetic energy is calculated by the following equation.

m= mass of the cars=26500kg
V=speed
E=kinetic energy
taking into account the above, the following equation is inferred
1= the cars are separated
2=
the cars are togheter
E1=E2

where
m= mass of each car
V1= 1.2m/s
Va=3.5,m/S

m= mass of each car
V=speed (in m/s) of the three coupled cars after the first couples with the other two
Solving



the speed of the three coupled cars after the first couples with the other two is 2.245m/s
B) Ice floats on top of liquid water and D) liquid is less dense than ice. The rest of the answers aren’t true because ice never sinks to the bottom of the water since ice is more dense than water.
Given that,
Output power = 87 W
Decibel reading = 120 dB
We need to calculate the intensity of sound
Using formula of intensity of sound

Put the value into the formula





We need to calculate the distance
Using relation of power out[ut and intensity

Put the value into the formula



Hence, The distance is 2.63 m