Complete Question
The complete question is shown on the
Answer:
The ascending order would be 2nd < 1st < 3rd
Explanation:
Generally the the Normal force is mathematically represented as
=> 
For the first drawing the value 
is between that of the the second and the third drawing so the Normal force would also be between the normal forces of the second and the third drawing
For the second drawing whose value of is less than that of the first and the third the normal force would also be less than that of the first and third
For the the third drawing whose value is (90°) which is higher than the first and the second the normal force would also be higher than the first and the second
Answer:
4.47 m/s.
Explanation:
distance traveled, d = 10 miles
time, t = 1 hour
Speed of the runner, v = d / t
Speed of the runner = 10 miles / 1
Speed of the runner = 10 mph
1 mph ----------------------- 0.44704 m/s
10 mph -----------------------?
= 4.47 m/s
Thus, in 2 hours the distance traveled will change but the speed it still 10 mph or 4.47 m/s.
The question is incomplete but still I answer to assume your thinking.
The picture is attached below!.
Here,
F is the force with which you pull up the incline.
N is the normal force.
w is the weight acting downward.
Axis are mentioned in the attached picture.
Concept:You can see there is no movement of object in the y-direction that means acceleration is zero in y-direction, sum of all the forces in y-direction equal to zero.
According to newton second law,
<span>∑ F = ma
</span>As, acceleration is zero in y-direction, so right hand side is zero in the above equation.
<span>∑ F = 0</span>
N-wcosθ=0
N= m*g*cos25°
N= m*(9.8)*(0.9063)
N= 8.8817*mBy putting the value of mass(m)(not given in the question) you will get the answer.
Hopefully, this is the answer of your question.
The maximum height attained is 460 m.
<h3>What is the maximum height?</h3>
We know that the final velocity of a body is 0 m/s at the maximum height which is the greatest height that is attained by the body. We now use the formula;
v^2 = u^2 -2gh
Given that v = 0 m/s
u^2 = 2gh
h = u^2/2g
v = final velocity
u = initial velocity
h = maximin height
g = acceleration due to gravity
h = (95)^2/2 * 9.8
h = 460 m
Learn more about maximum height:brainly.com/question/6261898
#SPJ1
