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3 years ago

Help me with geometry please picture below! :)

Mathematics

1 answer:

Lyrx [107]3 years ago

6 0

I hope this helps you

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?????????!!?????????????!!!????

Tasya [4]

Answer:

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3 years ago

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Look at the screenshot

BaLLatris [955]

Answer:66.6 but if round 67%

Step-by-step explanation:

Because 52 ÷78 =66.6

So it's 67%

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3 years ago

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Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball

Andru [333]

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and $51\frac{1}{3}$ yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from $51\frac{1}{3}$ yards.

$\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}$

Let us have a common denominator.

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}$

$\text{1 yard}=3\text{ feet}$

$\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}$

$\frac{28}{3}\text{ yards}=28\text{ feet}$

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

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3 years ago

- 1/2 (- 3/2x + 6x + 1) - 3x

zepelin [54]

Answer: = -2/4x + -1/2

Step-by-step explanation:

hope this helped

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3 years ago

Find the values of x and y

ale4655 [162]

Answer:

idek

Step-by-step explanation:

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2 years ago

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