Let
A------> (−3, −11)
B------> (6, 4)

step 1
find the slope m point A and point B
m=(y2-y1)/(x2-x1)-----> m=(4+11)/(6+3)----> m=15/9---> 5/3

step 2
with m=5/3 and point B (6, 4) find the equation of a line
y-y1=m*(x-x1)-----> y-4=(5/3)*(x-6)---> y=(5/3)x-6

case a. they have the same slope------> is not correct
because
y=35x−6------> the slope m=35
y=(5/3)x-6---> the slope m =5/3

case b. they have the same x-intercept.----> is not correct
because
the x-intercept is for y=0

y=35x−6-----> 0=35x-6----> 35x=6-----> x=6/35
the x-intercept is the point (6/35,0)

y=(5/3)x-6----> 0=(5/3)x-6----> (5/3)x=6---> x=18/5
the x-intercept is the point (18/5,0)

case c. the two lines are perpendicular. do. they have the same y-intercept-----> is nor correct
because

if two lines are perpendicular
m1*m2=-1-------> this condition is not satisfied

the y intercept is for x=0

y=35x−6-------> y=-6
the y intercept is the point (0,-6)

y=(5/3)x-6-----> y=-6
the y intercept is the point (0,-6)

they have the same y-intercept but the two lines are not perpendicular

see the attached figure

7 0

3 years ago