Answer:
Step-by-step explanation:
Given:
(y/y - 4) - (4/y + 4) = 32/y^2 - 16
Note y^2 - 16 = (y - 4 ) × (y + 4)
Multiplying the equation; both sides by y^2 - 16,
y (y + 4) - (4(y - 4)) = 32
y^2 + 4y - 4y + 16 = 32
y^2 = 32 - 16
Squaring both sides,
y = sqrt(16)
= 4
Write
, and recall that for a differentiable function
, the derivative at a point
is given by
which would suggest that for this limit,
and
. We have
, and so the value of the limit would be
.
It would be exactly $3.00
We know that
area of triangle=b*h/2
b=(x-2) m
Area=(x²-4) m²
h=?
(x²-4)=(x+2)*h/2
but remember that
(x²-4)=(x+2)*(x-2)
so
subsititute
(x+2)*(x-2)=(x+2)*h/2
(x-2)=h/2
h=2*(x-2)
the answer is
<span>the height of a triangle is 2*(x-2)</span>
