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dezoksy [38]
2 years ago
10

You want to use a coordinate proof to prove that midsegment DE of ABC is parallel to AC and half the length of AC. Which is the

best first step?

Mathematics
1 answer:
vazorg [7]2 years ago
4 0

Answer:

<em>the third one answer choice</em>

Step-by-step explanation:

<u><em>⊕ Place the triangle on a coordinate grid such that vertex A is at the origin, and segment AC lies on the x-axis.</em></u>

You will be able to see the length of segment AC and length of segment DE, and also will be able to see if AC║DE.

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What is the solution to 6|3x+5| less than equal to 14?
zimovet [89]
In this case there will be 2 solutions to solve for in this equation, both will equal plus and minus the answer. Which is 14.

6(3x + 5) = +_ 14

The solutions will be the following :

(14/6 - 5)/3

(-14/6 - 5)/3.
3 0
3 years ago
Choose the correct solution and graph for the inequality.
kupik [55]

Answer:

The first one..

Step-by-step explanation:

4 0
3 years ago
PLEASE HELP!!!!!!!!
Flura [38]

the answer is A ,when x=0,g(x)is-1,so when u add x into the g(x),which is  given below,u can find C,D,E,g(x) is no equal to -1,when you add x=1 into g(x)(A,B),you can find g(x) of B is 0,which is no equal the answer giving above(g(x)=2),but A is all right.

5 0
3 years ago
Answer ASAP. Please give correct answer. (Involves a bunch of circles and trig identities)
iren [92.7K]

Answer:

45.40

Step-by-step explanation:

First of all, the shape of rope is not a parabola but a catenary, and all catenaries are similar, defined by:

y=acoshxa

You just have to figure out where the origin is (see picture). The hight of the lowest point on the rope is 20 and the pole is 50 meters high. So the end point must be a+(50−20) above the x-axis. In other words (d/2,a+30) must be a point on the catenary:

a+30=acoshd2a(1)

The lenght of the catenary is given by the following formula (which can be proved easily):

s=asinhx2a−asinhx1a

where x1,x2 are x-cooridanates of ending points. In our case:

80=2asinhd2a

40=asinhd2a(2)

You have to solve the system of two equations, (1) and (2), with two unknowns (a,d). It's fairly straightforward.

Square (1) and (2) and subtract. You will get:

(a+30)2−402=a2

Calculate a from this equation, replace that value into (1) or (2) to evaluate d.

My calculation:

a=353≈11.67

d=703arccosh257≈45.40

7 0
2 years ago
What are three consecutive even integers whose sum is 66
irakobra [83]

Answer:

21,22,23

Step-by-step explanation: i love fried chicken look at my skin color

4 0
3 years ago
Read 2 more answers
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