You want to use a coordinate proof to prove that midsegment DE of ABC is parallel to AC and half the length of AC. Which is the
1 answer:
Answer:
<em>the third one answer choice</em>
Step-by-step explanation:
<u><em>⊕ Place the triangle on a coordinate grid such that vertex A is at the origin, and segment AC lies on the x-axis.</em></u>
You will be able to see the length of segment AC and length of segment DE, and also will be able to see if AC║DE.
You might be interested in
Answer:
165 students (hope it helps)
Step-by-step explanation:
300students - 45students = 255students
180students + 150students = 330students
330students / 2 = 165
Answer:
common difference: t2-t1
-2-6
-8
Answer:
The answer is 6
Step-by-step explanation:
This is a problem on edgeunity i have the extra context now.
The answer will be 11 lol
