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Free_Kalibri [48]
3 years ago
5

How many five-card hands (drawn from a standard deck) contain exactly three fives? (A five-card hand is any set of five differen

t cards.)
Mathematics
1 answer:
VashaNatasha [74]3 years ago
4 0

Answer:

4512.

Step-by-step explanation:

We are asked to find the number of five-card hands (drawn from a standard deck) that contain exactly three fives.

The number of ways, in which 3 fives can be picked out of 4 available fives would be 4C3. The number of ways in which 2 non-five cards can be picked out of the 48 available non-five cards would be 48C2.

4C3=\frac{4!}{3!(4-3)!}=\frac{4*3!}{3!*1}=4

48C2=\frac{48!}{2!(48-2)!}=\frac{48*47*46!}{2*1*46!}=24*47=1128

We can choose exactly three fives from five-card hands in 4C3*48C3 ways.

4C3*48C3=4*1128=4512

Therefore, 4512 five card hands contain exactly three fives.

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Need help with this math problem ASAP. Look at the picture attached. The linear function f(x) passes through the points (0,3) an
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♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

f(x) = 2x + 3

And

g(x) = 2 \times  {3}^{x}  \\

_________________________________

To find the y-intercept of any equation just need to put 0 (( zero )) instead of the x in the equation...

<h2>Let's do it....</h2>

_________________________________

In f ( x ) :

y - intercept = f(0)

f(x) = 2x + 3

f(0) = 2(0) + 3

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Thus :

y - intercept = 3

##############################

In g ( x ) :

y - intercept = g(0)

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_________________________________

The positive difference in the y-intercept value of f ( x ) and g ( x ) is :

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So write this in the box : 1

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And we're done....

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

8 0
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