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Free_Kalibri [48]
3 years ago
5

How many five-card hands (drawn from a standard deck) contain exactly three fives? (A five-card hand is any set of five differen

t cards.)
Mathematics
1 answer:
VashaNatasha [74]3 years ago
4 0

Answer:

4512.

Step-by-step explanation:

We are asked to find the number of five-card hands (drawn from a standard deck) that contain exactly three fives.

The number of ways, in which 3 fives can be picked out of 4 available fives would be 4C3. The number of ways in which 2 non-five cards can be picked out of the 48 available non-five cards would be 48C2.

4C3=\frac{4!}{3!(4-3)!}=\frac{4*3!}{3!*1}=4

48C2=\frac{48!}{2!(48-2)!}=\frac{48*47*46!}{2*1*46!}=24*47=1128

We can choose exactly three fives from five-card hands in 4C3*48C3 ways.

4C3*48C3=4*1128=4512

Therefore, 4512 five card hands contain exactly three fives.

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Answer:

The z score for bolt of diameter 18.12 mm is 1.20.

Step-by-step explanation:

Let <em>X</em> = diameter of bolts.

It is provided that the random variable <em>X</em> follows a Normal distribution with mean, <em>μ</em> = 18 mm and standard deviation, <em>σ</em> = 0.10 mm.

A <em>z</em>-score is a standardized score, a numerical, that defines how far a data value from the mean.

The distribution of <em>z</em>-scores is defined by the Standard Normal distribution.

Z\sim N(0, 1)

The formula to compute the <em>z</em>-score is:

z=\frac{x-\mu}{\sigma}

The value of the diameter of a bolt is, <em>x</em> = 18.12 mm.

Compute the <em>z</em>-score for this value as follows:

z=\frac{x-\mu}{\sigma}=\frac{18.12-18}{0.10}=\frac{0.12}{0.10}=1.20

Thus, the z score for bolt of diameter 18.12 mm is 1.20.

5 0
3 years ago
If f(x) = 3x + 2, what is f(5)?
Volgvan

Answer:

The 5 in the () is what the x is

Step-by-step explanation:

3(5)+2=17

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