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Illusion [34]
3 years ago
10

How do u solve 5x + 9 = x - 23 ? *EXTRA POINTS

Mathematics
2 answers:
iren [92.7K]3 years ago
7 0

Answer:

5x+9=x-23

5x-x=-23-9

4x= -32

4x/4=-32/4

x=-8

tatiyna3 years ago
3 0
5x - x = - 23 - 9

4x = - 32

X= -8
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Which line is perpendicular to y=2x+4?
steposvetlana [31]

Answer:

B

In the equation y=mx+b m is the slope of the line.

Therefore the coefficient in each of these equations is the slope.

A line with a perpendicular slope must have the inverse opposite of the actual line. For example if a line has a slope of 5, a perpendicular line to that line must have a slope of -1/5. If a line has a slope of 10, the perpendicular line has a slope of -1/10. If a line has a slope of 2 then the inverse opposite is -1/2 and that is the slope of the perpendicular line.

B is the only answer with the correct slope so B is the answer.

Step-by-step explanation:

6 0
3 years ago
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Anit [1.1K]
I think is C tbh sorry if that’s wrong my fault
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Ksivusya [100]
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Which is equivalent to 10(−225) ?
agasfer [191]

Answer:

2250.        hope this helps!

Step-by-step explanation:

Multiply  10 225

5 0
3 years ago
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Raj tested his new flashlight by shining it on his bedroom wall. The beam of light can be described by the equation . How many i
Molodets [167]

Answer:

12 inches

Step-by-step explanation:

Raj tested his new flashlight by shinning it on his bedroom wall the beam of the light can be described by the equation (x^2-2x) + (y^2-4y) - 31=0. how many inches wide is the beam of light on the wall

Solution

Given:

(x^2-2x) + (y^2-4y) - 31=0

By completing the square

(x^2-2x) + (y^2-4y) - 31=0

(x^2-2x+1-1) + (y^2-4y+4-4)-31=0

(x-1)^2 -1 + (y-2)^2 - 4 - 31=0

(x-1)^2 + (y-2)^2 - 1 - 4 - 31=0

(x-1)^2 + (y-2)^2 - 36=0

(x-1)^2 + (y-2)^2=36

Writing the equation in the form: (x-h)^2+(y-k)^2=r^2

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From the above, r=6

Where,

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radius=6

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=2×6

=12 inches

6 0
3 years ago
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