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Greeley [361]
3 years ago
5

What is 15/y+11 - 10/y+3 = 0

Mathematics
2 answers:
meriva3 years ago
5 0
For this case we have the following expression:
 \frac{15}{y}+11-\frac{10}{y}+3=0
 What we must do for this case is to place the variables on the left side of the equation and the constants on the right side of the equation.
 We have then:
 \frac{15}{y}-\frac{10}{y}=-11-3
 Rewriting the expression we have:
 \frac{15-10}{y}=-14
 \frac{5}{y}=-14
 Then, clearing the value of y we have:
 \frac{-5}{14}=y
 Answer:
 
The value of the variable y is:
 
\frac{-5}{14}=y

Scrat [10]3 years ago
3 0
15/y+11-10/y+3=0
15/y-10/y=5/y  11+3=14
5/y+14=0
o-14=-14
5/y=-14
y=-5/14
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The price of tomatoes went from $1.12 per pound to $1.96 per pound in 3 years. find the rate of change of the price of tomatoes.
ad-work [718]

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7 0
3 years ago
Solve the following system of equations express your answer as an ordered pair in the format of (a,b) with no spaces between the
Alekssandra [29.7K]
Once we find what x and y is, that's where they intercept and we can write that as an ordered pair as (x,y) Now we need to find what y is. So let's put x into the original first equation 3x+4y=16 3(4)+4y=16 12+4y=16 ---Subtract 12 from both sides 4y=4 ---Divide both sides by 4 y=1 Alright, so our ordered pair is (4,1) 
5 0
3 years ago
Plz help!
beks73 [17]

First, you need to find the derivative of this function.  This is done by multiplying the exponent of the variable by the coefficient, and then reducing the exponent by 1.  

f'(x)=3x^2-3

Now, set this function equal to 0 to find x-values of the relative max and min.

0=3x^2-3

0=3(x^2-1)

0=3(x+1)(x-1)

x=-1, 1

To determine which is the max and which is the min, plug in values to f'(x) that are greater than and less than each.  We will use -2, 0, 2.

f'(-2)=3(-2)^2-3=3(4)-3=12-3=9

f'(0)=3(0)^2-3=3(0)-3=0-3=-3

f'(2)=3(2)^2=3(4)-3=12-3=9

We examine the sign changes to determine whether it is a max or a min.  If the sign goes from + to -, then it is a maximum.  If it goes from - to +, it is a minimum.  Therefore, x=-1 is a relative maximum and x=1 is a relative miminum.

To determine the values of the relative max and min, plug in the x-values to f(x).

f(-1)=(-1)^3-3(-1)+1=-1+3+1=3

f(1)=(1)^3-3(1)+1=1-3+1=-1

Hope this helps!!

7 0
4 years ago
A population of 30 deer is introduced into a wildlife sanctuary. It is estimated that the sanctuary can sustain up to 200 deer,
gogolik [260]

Answer:

After one year the population will be 33 deers, and after two years it will be 36 deers.

Step-by-step explanation:

Given that a population of 30 deer is introduced into a wildlife sanctuary, and it is estimated that the sanctuary can sustain up to 200 deer, and absent constraints, the population would grow by 10% per year, to predict the population after one year and after two years, the following calculations must be performed:

A)

30 x 1.1 = X

33 = X

B)

30 x 1.1 ^ 2 = X

30 x 1.21 = X

36.3 = X

Therefore, after one year the population will be 33 deers, and after two years it will be 36 deers.

7 0
3 years ago
The organizer of a television show must select 5 people to participate in the show. The participants will be selected from a lis
Lemur [1.5K]
5/30 But you should say how many young people there are because for all we know all 30 could be young
3 0
4 years ago
Read 2 more answers
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