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Flura [38]
3 years ago
5

Minimize q=5x^2+3y^2 where x+y=8

Mathematics
1 answer:
WARRIOR [948]3 years ago
5 0
Q=5*x^2+3*(8-x)^2
dq/dx=10x-6(8-x)=16x-48....1
To minimise q dq/dx=0......2
x=3 and y=5 on solving 1&2
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shtirl [24]
-5 because a negative plus a negative is a positive this is why it is the right answer
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How many times larger is 3 x 1015 than 6 x 1010
Deffense [45]

it is 3,000 times larger! that is the difference.

8 0
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In a plot of probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum
Lunna [17]

In a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs (A) at a0. the first Bohr radius.

<h3>What is an electron?</h3>
  • The electron is a subatomic particle with a negative one elementary charge electric charge.
  • Electrons are the first generation of the lepton particle family and are widely regarded as elementary particles due to the lack of known components or substructure.

Electron in the hydrogen:

  • Hydrogen has the simplest electron configuration to write because it just contains one electron.
  • There is essentially only one electron surrounding the Hydrogen nucleus.
  • Because hydrogen only has one electron, its configuration is 1s1.
  • The maximum occurs at a0, the first Bohr radius, in a plot showing the chance of finding the electron in the hydrogen ground state vs the distance from the nucleus.

Therefore, in a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs (A) at a0. the first Bohr radius.

Know more about electrons here:

brainly.com/question/860094

#SPJ4

The complete question is given below:

In a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs:

A. at a0. the first Bohr radius

B. at slightly less than a0

C. at slightly more than a0

D. at 2 a0

E. at a0/2

6 0
2 years ago
Complete the equations so that the solution of the system of equations is (−1, −4). y= ?X−11 6x− ? Y=10
eimsori [14]

Answer:

y = –7x – 11

6x – 4y = 10

Step-by-step explanation:

From the question given above, we obtained:

x = –1

y = –4

y = ?x – 11 ....... (1)

6x – ?y = 10b......... (2)

Let the two unknown be a and b. Thus the above equation becomes:

y = ax – 11 ......... (3)

6x – by = 10 .......(4)

Next, we shall determine the value of 'a' and 'b'. This can be obtained as follow:

For a:

y = ax – 11

x = –1

y = –4

–4 = a(–1) – 11

–4 = –a – 11

Collect like terms

–4 + 11 = –a

7 = –a

Multiply through by –1

a = –7

For b:

6x – by = 10

x = –1

y = –4

6(–1) – b(–4) = 10

–6 + 4b = 10

Collect like terms

4b = 10 + 6

4b = 16

Divide both side by 4

b = 16 / 4

b = 4

Finally, we shall substitute the value of a and be into equation 3 and 4 respectively.

y = ax – 11

a = –7

y = –7x – 11

6x – by = 10

b = 4

6x – 4y = 10

Therefore, the complete equation are:

y = –7x – 11

6x – 4y = 10

8 0
3 years ago
If x 2 = x + 1, find x 3 , giving your answer in the form ax + b.
GalinKa [24]

Answer:

{x}^{2}  = x + 1 \\ x =  {x}^{2}  - 1 \\  {x}^{3}  =  { ({x}^{2}  - 1)}^{3}  \\  = (x - 1) {}^{3} (x + 1) {}^{3}

4 0
3 years ago
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