Answer:
1-2y+y^2
Step-by-step explanation:
(1–y)^2
(1-y) * (1-y)
FOIL
first: 1*1 =1
outer: 1*-y = -y
inner: -y *1 = -y
last: -y*-y = y^2
Add together: 1+-y-y+y^2
1-2y+y^2
Answer:
The height of the tank in the picture is:
Step-by-step explanation:
First, to know the height of the tank, we're gonna change the unit of the volume given in liters to cm^3:
- <em>1 liter = 1000 cm^3</em>
So:
- <em>1.2 liters = 1200 cm^3</em>
Now, we must calculate the height of the tank that we don't know (the other part that isn't with water), to this, we can use the volume formula clearing the height:
- Volume of a cube = long * wide * height
Now, we must clear the height because we know the volume (1200 cm^3):
Height = volume of a cube / (long * wide)
And we replace:
- Height = 1200 cm^3 / (12 cm * 8 cm)
- Height = 1200 cm^3 / (96 cm^2)
- Height = 12.5 cm
Remember this is the height of the empty zone, by this reason, to obtain the height of the whole tank, we must add the height of the zone with water (7 cm) that the exercise give us:
- Heigth of the tank = Height empty zone + height zone with water
- Heigth of the tank = 12.5 cm + 7 cm
- <u>Heigth of the tank = 19.5 cm</u>
In this form, <u>we calculate the height of the tank in 19.5 cm</u>.
Your answer is B. I hope this is helpful!
So plug in 10 for r which would give you 3(10)=10+5s the multiply 3x10 so you should have 30=10+5s you want to get 5s by its self to subtract 10 to both sides so you should get 20=5s them divide 5 to both sides and you get s=4
This can be rewritten to
20/100 or 0.2.
Hope this helps :)
