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erik [133]
2 years ago
10

In detail explain how to multiply in binomial of (5x-7 (2x-1) in foil method

Mathematics
1 answer:
Nesterboy [21]2 years ago
4 0

Step-by-step explanation:

First

Outer

Inner

Last

First- 5x*2x=10x^2

Outer-5x*-1= -5x

Inner--7*2x= -14x

Last- -7*-1= 7

10x^2-5x-14x+7

you can simplify it further however thats the answer

You might be interested in
A jar contains 46 quarters and pennies. The total value of the coins is $4.30. Which system of equations can be used to find p,
Crazy boy [7]

Answer:

16 quarters

30 pennies

Step-by-step explanation:

q= quarters

p=pennies

set up a system of equations. One equation is for total value, the other is total # of coins.

q + p = 46

0.25q + 0.01p = 4.30 -> multiply this equation by 4 so you can subtract from the top equation

q + P =46

1q + 0.04p = 17.20

subtract the bottom equation from the top

0.96p = 28.8

divide by 0.96

p=30

substitute p in the top equation

q + 30 = 46

subtract 30 from both sides

q = 16

4 0
3 years ago
Please help me with this
BARSIC [14]
Chance has 90.72 grams in coins
6 0
3 years ago
one night a theater sold 548 movie tickets. an adult’s costs $6.50 an child’s cost $3.50. in all, $2,881 was takin in. how many
gavmur [86]

Answer:

  • 321 adult tickets
  • 227 child tickets

Step-by-step explanation:

This sort of problem is easily solved by defining a variable to be the quantity of the higher-value contributor. Here, we can let x represent the number of adult tickets. Then total revenue is ...

  6.50x +3.50(548-x) = 2881

  3x +1918 = 2881 . . . . . . . . . . . . eliminate parentheses, collect terms

  3x = 963 . . . . . . . . . . . . . . . . . . subtract 1918

  x = 321 . . . . . . . . . . . . . . . . . . . . divide by 3

  548-x = 548 -321 = 227 . . . . . .number of child tickets

321 adult tickets and 227 child tickets were sold.

3 0
3 years ago
Please help me solve this equation and show the work show me how you got the answer
Nesterboy [21]

Answer: k=3

Step-by-step explanation:

To solve for k, you want to isolate k.

\frac{2}{5} (5k+35)-8=12            [add both sides by 8]

\frac{2}{5} (5k+35)=20                  [multiply both sides by 5/2]

5k+35=50                       [subtract both sides by 35]

5k=15                               [divide both sides by 5]

k=3

Now, we know that k=3.

7 0
3 years ago
The sum of the prime numbers between 40 and 50
kramer

Answer:

Step-by-step explanation:

Prime numbers are numbers that only have two divisors of 1 and itself.

PRIME NUMBERS INCLUDED BETWEEN 40 AND 50 =

41.43.47.

41 + 43 + 47 = 131

4 0
3 years ago
Read 2 more answers
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