A single die is rolled twice. the set of 36 equally likely outcomes is {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1),
Maksim231197 [3]
<span>We need to find the rolls whose sum is greater than 10. By looking at the outcomes, we see that (5,6), (6,5), and (6,6) all have a sum greater than 10. Therefore, there are 3 chances to get a sum greater than 10. Since there are 36 chances overall, the probability of rolling greater than 10 are 3/36 = 1/12.</span>
To find area you multiply the height and width so which ever are the height and width out of those numbers you multiply them together
Answer:
Step-by-step explanation:
Apply the Pythagorean Theorrem. Find the sum of the squares of the two shortest sides and determine whether this sum equals the square of the longest side:
#19: 5^2 + 12^2 = ? = 13^2
25 + 144 = ? = 169 This is true, so you do have a right triange in #19.
#21: 2^2 + 4^2 = ? = 7^2, or 4 + 16 = ? = 49 This is false. Not a right
triangle.
Apply this same approach (Pythagorean Theorem) to the remaining problems.
Answer:
0.44
Step-by-step explanation:
Answer:
B.(-5,-7)
Step-by-step explanation:
According to the rule of rotation if you were to have a 270* clockwise you would first switch the x and y values. Ex: (-7,5) -> (5,-7). next you would make the original y coordinate a negative. (5,-7) -> (-5,-7).
