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Pachacha [2.7K]
3 years ago
7

Can someone please help me?(Fill in the blanks) This is on Khan Academy too, I need it ASAP! if you answer right I'll mark you B

RAINLIEST. ​

Mathematics
1 answer:
Travka [436]3 years ago
7 0

First divide both sides by 2:

2x^2+7x+6=0\implies x^2+\dfrac72x+3=0

Move the constant term to the right side:

x^2+\dfrac72x=-3

Since

(x+y)^2=x^2+2xy+y^2

we want to have

2y=\dfrac72\implies y=\dfrac74

Then

\left(x+\dfrac74\right)^2=x^2+\dfrac72x+\dfrac{49}{16}

So in our equation, we need to add 49/16 to both sides in order to complete the square:

x^2+\dfrac72x+\dfrac{49}{16}=-3+\dfrac{49}{16}

\implies\left(x+\dfrac74\right)^2=\dfrac1{16}

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