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Fudgin [204]
3 years ago
15

Please helpppppppppppppppppppp

Mathematics
2 answers:
kvv77 [185]3 years ago
7 0

Answer:

2.778

Step-by-step explanation:

riadik2000 [5.3K]3 years ago
3 0

Answer:

c  I think and I give up

Step-by-step explanation:

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Please help me out with thissssss<br><br> No links no stealing points
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Answer:

yes

Step-by-step explanation:

congurency property can be used for all right angles triangles

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3 years ago
Factor the polynomial?<br> 2x^2+4x^2+6x^3
tatiyna
2 x^{2} + 4 x^{2} + 6 x^{3}
= 6 x^{2} + 6 x^{3}
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3 0
3 years ago
If 8 cents are needed to buy 10 pebbles, how many dollars are needed to buy 205 pebbles?
stira [4]

Answer:

Hello There!!

Step-by-step explanation:

If 8 cents=10 pebbles then do 205 divided by 10 which is 20.5 . So, 8×20.5=164 dollars.

(8×20.5=164) 8 cents=10 (10×20.5=205)

164 dollars=205

Therefore,the answer is 164 dollars.

hope this helps,have a great day!!

~Pinky~

7 0
3 years ago
Is the SAT or ACT easier?
ivann1987 [24]
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3 0
3 years ago
A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte
ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, q_1 = Q- r \times Q

q_1 = Q(1-r)\cdots(i)

The value of quantity after 2 months, q_2 = q_1- r \times q_1

q_2 = q_1(1-r)

From equation (i)

q_2=Q(1-r)(1-r)  \\\\q_2=Q(1-r)^2\cdots(ii)

The value of quantity after 3 months, q_3 = q_2- r \times q_2

q_3 = q_2(1-r)

From equation (ii)

q_3=Q(1-r)^2(1-r)

q_3=Q(1-r)^3

Similarly, the value of quantity after n months,

q_n= Q(1- r)^n

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

q_{48}=Q(1-r)^{48}

Putting Q=6200 and r=5.5%=0.055, we have

q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32

Hence, the value of quantity after 4 years is 410.32.

4 0
3 years ago
Read 2 more answers
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