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nikklg [1K]
3 years ago
9

How many solutions does the system of equations have

Mathematics
1 answer:
polet [3.4K]3 years ago
7 0
2x - 9y = -5
4x - 6y = 2

multiple first equation by 2:

4x - 18y = -10
4x - 6y = 2

Subtract 2 from 1:

-12y = -12
y = 1

Now plug y=1 into any equation. I go with second:

4x - 6(1) = 2

4x - 6 = 2
4x = 8
x = 2

So the solution is (2,1) therefore there is one solution.
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Answer:

C=14\pi\ in

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we have

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Examine the diagram of circle V, where two chords, JK and LM, are equidistant from the center. If JK=4x+37, and LM=5(x+5), what
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we know that

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so

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3 years ago
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4 years ago
Find an equation for the perpendicular bisect or of the line segment whose end points are (-2,-4) and (8,2)
Serhud [2]

Answer:

, you must find the midpoint of the segment, the formula for which is

(

x

1

+

x

2

2

,

y

1

+

y

2

2

)

. This gives

(

−

5

,

3

)

as the midpoint. This is the point at which the segment will be bisected.

Next, since we are finding a perpendicular bisector, we must determine what slope is perpendicular to that of the existing segment. To determine the segment's slope, we use the slope formula

y

2

−

y

1

x

2

−

x

1

, which gives us a slope of

5

.

Perpendicular lines have opposite and reciprocal slopes. The opposite reciprocal of

5

is

−

1

5

.

We now know that the perpendicular travels through the point

(

−

5

,

3

)

and has a slope of

−

1

5

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Solve for the unknown

b

in

y

=

m

x

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b

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3

=

−

1

5

(

−

5

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+

b

⇒

3

=

1

+

b

⇒

2

=

b

Therefore, the equation of the perpendicular bisector is

y

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−

1

5

x

+

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4 0
3 years ago
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