Ask question

Ask question

All categories

3 years ago

14

a box of fruit contains 2 peaches, 3 bananas, 4 strawberries, and 3 plums. what fraction of the fruit in the box is either peach

es or plums?

1 answer:

lubasha [3.4K]3 years ago

3 0

Well 5 out of the 12 are peaches or plums

You might be interested in

A total of 150 students have taken an Algebra 2 final exam. The scores are normally distributed with a mean of 71% and standard

WARRIOR [948]

Answer:

102 students

Step-by-step explanation:

Note that 65% and 71% are both 1 standard deviation from the mean (71%). According to the empirical rule, 68% of scores lie within 1 std. dev. of the mean.

68% of 150 students would be 0.68(150 students) = 102 students

3 0

3 years ago

Maria wants to buy a new bicycle that costs $129.89. She has saved $78 of her babysitting money. Maria’s grandfather gave her $2

Makovka662 [10]

Answer:

more than what she has

Step-by-step explanation:

6 0

3 years ago

Find the measure of angle X.

Alik [6]

The triangle is an isosceles triangle so that means the base angles must be congruent.

The sum of the interior angles of a triangle add up to 180 degrees.

Subtract 52 degrees from 180 degrees.

180 - 52 = 128

Divide 128 degrees by 2.

128/2 = 64

m∠X = 64°

8 0

4 years ago

Read 2 more answers

Find the area of a rectangle that is 17 3/8 in. By 4 1/9 in.

timama [110]

Answer:

71 31/72 in

Step-by-step explanation:

multiply the length and width for the formula. :)

4 0

3 years ago

Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.

Leya [2.2K]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}$

$\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}$

$\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 2}\implies A=6500(1.12)^2\implies A=8153.6$

6 0

3 years ago