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Viktor [21]
3 years ago
9

In the bin there is a 45% chance of randomly selecting ripe avocados. If you are picking avocados from the bin, you keep inspect

ing avocados and stop upon finding a ripe avocado. If you buy a bag of avocados, you do not inspect the fruit until you get home and inspect the bag of avocados all at once.
1. What is the probability that you have inclusively between 2 and 3 ripe avocados from your bag of 5 avocados?
2. What is the probability that you inspect inclusively 3 and 3 avocados from the bin?
Mathematics
1 answer:
Archy [21]3 years ago
7 0

Answer:

0.6125

Step-by-step explanation:

We have,

P(ripe avocados) = 0.45 , n = 5

by binomial distribution,

P(x=k) = ${\overset{n}C}_k P^k(1-P)^{n-k}$

P(2 ≤ x ≤ 3) = P(x=2) + P(x=3)

P(x=2) = ${\overset{5}C}_2(0.45)^2(0.55)^3$

           = 10 x (0.45)² x (0.55)³

           = 0.3369

P(x=3) = ${\overset{5}C}_3(0.45)^3(0.55)^2$

           = 10 x (0.45)³ x (0.55)²

           = 0.2756

So, P(2 ≤ x ≤ 3 ) = 0.3369 + 0.2756

                          = 0.6125

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3 years ago
I have 14 Baseballs in 23 tennis balls and some boxes of baseballs with 12 baseball and I have the equal amount of boxes of tenn
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Answer:

The answer is below

Step-by-step explanation:

I have 14 Baseballs in 23 tennis balls. I bought some boxes of baseballs with 12 baseball to a box and equal amount of boxes of tennis balls with 16 balls to a box. write an expression to represent the total number of balls

Solution:

Let n represent the number of boxes of each type.

Given, the number of boxes of tennis = number of boxes of baseball, hence:

n = number of boxes of tennis = number of boxes of baseball.

Already I have 14 baseball and I bought boxes of baseballs with 12 baseball to a box, therefore:

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I have 23 tennis ball and I bought boxes of tennis balls with 16 baseball to a box, therefore:

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5 0
3 years ago
Using appropriate properties find: 2/3 × 3/4 + 3/7 × 3/4​
Viktor [21]

Answer:

\frac{23}{28}

Step-by-step explanation:

\frac{2}{3}  \times  \frac{3}{4}  +  \frac{3}{7}  \times  \frac{3}{4}

=  >  \frac{3}{4} ( \frac{2}{3}  +  \frac{3}{7} )

=  >  \frac{3}{4}  \times  \frac{23}{21}

Reducing 3 from numerator and denominator,

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3 0
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pshichka [43]

Answer:

a. 90º

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The chords ST and RA intesect at Y, so that SY is now perpendicular to RY and they form an angle 90 degrees at that point. However angles mSA and mRT are both at the circumference of the circle(a chord is a line from point of a circle's circumference to the other) and are both 90 degrees because angle at the circumference is half of angle at the centre in same arc.

6 0
3 years ago
15 points to answer this question
Mamont248 [21]

it is none since there is no relation

4 0
4 years ago
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