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irakobra [83]
3 years ago
7

Jason jogs around a circular track at an average rate of 3 laps in 5 minutes. At this rate, how many laps can Jason complete in

35 minutes?
A. 7
B. 15
C. 21
D. 58
Mathematics
2 answers:
Nata [24]3 years ago
4 0
The answer is C because 35 divided by 5 is 7 and 7 times 3 is 21

You have to see how many groups of 5 can go in 35 and then you multiply the amount of groups with the amount of laps Jason can jog in 5 minutes and you get 21
Alexxandr [17]3 years ago
3 0
C.) 21
Jason will complete 21 laps in 35 minutes.


To solve this, you would have to set up a proportion to find the missing term

3 laps / 5 minutes = “x” laps / 35 minutes

Multiply the numerator of the first fraction (3) by the denominator of the second fraction (35)

3 * 35 = 105

Divide 105 by the denominator of the first fraction (5)

105 / 5 = 21
So... x = 21 laps
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Option C:

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Given expression:

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$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}

$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}

$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}

$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}

Substitute these into the above expansion.

(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}

The coefficient of x^{2} y^{3} is 40.

Option C is the correct answer.

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