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irakobra [83]
3 years ago
7

Jason jogs around a circular track at an average rate of 3 laps in 5 minutes. At this rate, how many laps can Jason complete in

35 minutes?
A. 7
B. 15
C. 21
D. 58
Mathematics
2 answers:
Nata [24]3 years ago
4 0
The answer is C because 35 divided by 5 is 7 and 7 times 3 is 21

You have to see how many groups of 5 can go in 35 and then you multiply the amount of groups with the amount of laps Jason can jog in 5 minutes and you get 21
Alexxandr [17]3 years ago
3 0
C.) 21
Jason will complete 21 laps in 35 minutes.


To solve this, you would have to set up a proportion to find the missing term

3 laps / 5 minutes = “x” laps / 35 minutes

Multiply the numerator of the first fraction (3) by the denominator of the second fraction (35)

3 * 35 = 105

Divide 105 by the denominator of the first fraction (5)

105 / 5 = 21
So... x = 21 laps
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e) 0.57

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Step-by-step explanation:

To answer this problem, a Venn diagram should be useful. The diagram with the information of Event 1 and Event 2 is shown below (I already added the information for the intersection but we're going to see how to get that information in the b) part of the problem)

Let's call A the event that she passes the first course, then P(A)=.73

Let's call B the event that she passes the second course, then P(B)=.66

Then P(A∪B) is the probability that she passes the first or the second course (at least one of them) is the given probability. P(A∪B)=.98

b) Is the event she passes one course independent of the event that she passes the other course?

Two events are independent when P(A∩B) = P(A) * P(B)

So far, we don't know P(A∩B), but we do know that for all events, the next formula is true:

P(A∪B) = P(A) + P(B) - P(A∩B)

We are going to solve for P (A∩B)

.98 = .73 + .66 - P(A∩B)

P(A∩B) =.73 + .66 - .98

P(A∩B) = .41

Now we will see if the formula for independent events is true

P(A∩B) = P(A) x P(B)

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.41 ≠.4818

Therefore, these two events are not independent.

c) The probability she does not pass either course, is 1 - the probability that she passes either one of the courses (P(A∪B) = .98)

1 - P(A∪B) = 1 - .98 = .02

d) The probability she doesn't pass both courses is 1 - the probability that she passes both of the courses P(A∩B)

1 - P(A∩B) = 1 -.41 = .59

e) The probability she passes exactly one course would be the probability that she passes either course minus the probability that she passes both courses.

P(A∪B) - P(A∩B) = .98 - .41 = .57

f) Given that she passes the first course, the probability she passes the second would be a conditional probability P(B|A)

P(B|A) = P(A∩B) / P(A)

P(B|A) = .41 / .73 = .5616

4 0
3 years ago
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