1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
postnew [5]
3 years ago
6

Order of operations (GEMS)

Mathematics
1 answer:
cestrela7 [59]3 years ago
3 0
(6+2*3)/(9-7)^2
(6+6)/(2)^2
12/4
3

Final answer: 3
Remember to simplify within parentheses first and then divide the two values in the end.
You might be interested in
Jamie needs 1/5 meter of ribbon to decorate the border of a photo frame. Enter the number of photo frames that can be decorated
charle [14.2K]

Answer:

<em><u>4</u></em><em><u> </u></em><em><u>photo</u></em><em><u> </u></em><em><u>frames</u></em><em><u> </u></em>

Step-by-step explanation:

<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em>

8 0
3 years ago
Read 2 more answers
Find the equation of the linear function represented by the table below in slope-intercept form. x y 1 2 2 7 3 12 4 17
Mila [183]

Answer:

Step-by-step explanation:

(1, 2) (2, 7)

(7-2)/(2 - 1) = 5/1= 5

y - 2 = 5(x - 1)

y - 2 = 5x - 5

y = 5x - 3

7 0
3 years ago
What is measure of angle R?
Aleks [24]
The given triangle is a right triangle.
The tangent of an angle of right triangle is obtained by dividing the opposite side of the angle with the adjacent side of the angle.
The opposite side of angle R is 5 cm and the adjacent side of angle R is 12 cm.

tan R = 5 / 12 = 0.4167
R = arctan (0.4167) = 22.6 degrees.
4 0
3 years ago
2 triangles are shown. The first triangle has side lengths 35, 20, and 20. The second triangle has side lengths x, 44, 44.
Ad libitum [116K]

The value of x is 77 cm which will make the triangles similar by SSS similarity theorem

Given length of the three sides of one triangle are  35 , 20 and 20

and length of the three sides of another triangle are  x, 44,44

We need to find the values of x by using SSS Similarity theorem

We know that triangles are are similar by side - side - side similarity creation and hence the sides are in the same ratio

As both the triangles are isosceles triangles

Therefore ,

x/35 = 44/20=44/20 (Using ratio)

Solving the equation we get

x=44*35/20

x= 77

Hence the value of x is 77cm

Learn more about similarity of triangles here brainly.com/question/14285697

#SPJ10

8 0
2 years ago
Is a parallelogram always a square?<br> yes<br> no
polet [3.4K]

Answer:

yes

Step-by-step explanation:

4 0
3 years ago
Other questions:
  • What is 310,763,136 in word form?
    7·2 answers
  • At a local sporting goods store, employees get paid a commission that is 6% of their sales. gina's sales for the week was $441.0
    13·2 answers
  • -2 -1 0 1 2 fx 1/8 1/4 1/2 1 2 what is the initial value of the exponential function represented by the table
    15·1 answer
  • Over summer, a dam’s water volume reduces from 20 megalitres to 4 megalitres. What fraction of the water in the dam has been los
    8·1 answer
  • If the height of a rectangle is 4.8m and the base is 8.4, what is the perimeter of the rectangle
    7·2 answers
  • Diego measured the length of a pen to be 22 cm. The actual length of the pen is 23 cm. Which of these is closest to the percent
    6·2 answers
  • How would changes in sample size affect the margin of error, assuming all else remained constant?
    6·1 answer
  • . There are 10 beads in a bag. 5 beads are black; 3 beads are white and the rest are red. A bead is picked at random. Find the p
    5·1 answer
  • HELLLLLPPPPPPPP!!!!!!!!!!!!! IT GOT DELETED LAST TIME!!!!!!<br><br> 4x^3y^2 x 3x^6y^3/24x^11y^2
    5·1 answer
  • If each student needs 1/3 of a stick of clay to do an art project,and there are 4 sticks of clay, how many students can do the a
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!