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3 years ago

Order of operations (GEMS)

Mathematics

1 answer:

cestrela7 [59]3 years ago

3 0

(6+2*3)/(9-7)^2
(6+6)/(2)^2
12/4
3

Final answer: 3
Remember to simplify within parentheses first and then divide the two values in the end.

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How do I do number 14?

luda_lava [24]

Answer:

1/4^3 = 1/64

Step-by-step explanation:

you just basically multiply 1/4 for the first 3 ones, you multiply $\frac{1}{4} x\frac{1}{4} x\frac{1}{4} = \frac{1}{64}$ . then you do the same but twice and then once.

3 0

3 years ago

Read 2 more answers

Find the measure of angle T

sukhopar [10]

Answer:

100 degrees

Step-by-step explanation:

The measure of angle T is 100 degrees.

5 0

3 years ago

At a certain high school, 15 students play stringed instruments and

Aleks [24]

Answer:

0 is the probability that a randomly selected student plays both a stringed and a brass instrument.

Step-by-step explanation:

Given that:

Number of students who play stringed instruments, N(A) = 15

Number of students who play brass instruments, N(B) = 20

Number of students who play neither, N( $A \cup B$ )' = 5

To find:

The probability that a randomly selected students plays both = ?

Solution:

Total Number of students = N(A)+N(B)+N( $A \cup B$ )' =15 + 20 + 5 = 40

(As there is no student common in both the instruments we can simply add the three values to find the total number of students)

As per the venn diagram, no student plays both the instruments i.e.

$N(A\cap B) =0$

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(A\cap B) = \dfrac{N(A\cap B)}{N(U)}\\\Rightarrow \dfrac{0}{40}\\\Rightarrow P(A\cap B) = 0$

So, 0 is the probability that a randomly selected student plays both a stringed and a brass instrument.

5 0

3 years ago

If T(n)=6n-1what is the first term

OleMash [197]

So if you find the 1st term, you should write 1 instead of n
T1 = 6.1 -1
T1= 6-1
T1= 5
Hope it helps!
#MissionExam001

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%203%20000%20000%5E%7B2%7D%20%20" id="TexFormula1" title=" 3 000 000^{2} " alt=" 3 000 000^{2

Pachacha [2.7K]

${3000000}^{2} + {4000000}^{2} \\ \\ {10}^{6} ( {3}^{2} + {4}^{2} ) \\ \\ {10}^{6} \times 25 \\ \\ 25000000 \: \: \: \: \: Ans.$

8 0

3 years ago