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3 years ago

If x negative squared = 16, what is the value of x squared?

Mathematics

2 answers:

Firlakuza [10]3 years ago

6 0

I think it a because 1over 16 can equal positive 16

OLEGan [10]3 years ago

4 0

Answer:

Step-by-step explanation:

$x^{-2}=16\\\\\frac{1}{x^{2}}=16\\\\$

Cross multiplication,

$1=16x^{2}\\\\\frac{1}{16}=x^{2}$

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2 six-sided dice, one green and one red, are released. What is the probability that : The number on the red die is 3

prisoha [69]

1/6 bc they all have an equal chance to be all the numbers on the die and their is only 6 numbers on the die so you have 1:6 probability of it being 3

5 0

1 year ago

Please give me the answer quick

Vlada [557]

Answer:

MON= 57

Step-by-step explanation:

5x-23+3x-15=90

8x-38=90

8x=128

x=16

PLUG 16 INTO MON EQUATION

5(16)-23=57

therefore,

MON=57

USE COMPLEMENTARY FOR PROBLEMS LIKE THIS :)))

(btw, assuming that the angle is 90 degrees)

3 0

3 years ago

Please help quickly !!

Nataly_w [17]

Answer:

16.5x == 465.3

Step-by-step explanation:

To find the rate , take the number of miles and divide by the gallons

rate = 465.3 / 16.5

Let the rate be x

x = 465.3 / 16.5

Multiply each side by 16.5

16.5x = 465.3

6 0

3 years ago

Let f (x) = 3x − 1 and ε > 0. Find a δ > 0 such that 0 < ∣x − 5∣ < δ implies ∣f (x) − 14∣ < ε. (Find the largest

s344n2d4d5 [400]

Answer:

This proves that f is continous at x=5.

Step-by-step explanation:

Taking f(x) = 3x-1 and $\varepsilon>0$ , we want to find a $\delta$ such that $|f(x)-14|$

At first, we will assume that this delta exists and we will try to figure out its value.

Suppose that $|x-5|$ . Then

$|f(x)-14| = |3x-1-14| = |3x-15|=|3(x-5)| = 3|x-5|< 3\delta$ .

Then, if $|x-5|$ , then $|f(x)-14|$ . So, in this case, if $3\delta \leq \varepsilon$ we get that $|f(x)-14|$ . The maximum value of delta is $\frac{\varepsilon}{3}$ .