Answer:
After 121 passes, there will be 11 cups facing up
Step-by-step explanation:
Given that:
Peter initially lines up 121 cups facing down in a straight line from left to right and consecutively labels them from 1 to 121.
We can have an inequality ; i.e 1 ≤ n ≤ 121; if n represents the divisor including n itself for which n = odd number. Thus at the end of this claim, the cup will be facing up.
On the ith pass, he flips over cups i, 2i, 3i, 4i,.... (By "flip," we mean changing the cup from face down to face up or vice versa.)
For each divisor on the ith pass of n;
since we are dealing with possibility of having an odds number:
Thus;
and
where ; n = perfect square.
Thus ; we will realize that between 1 to 121 ; there exist 11 perfect squares. Therefore; as a result of that ; 11 cups will definitely be facing up after 121 passes
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Answer:
Step-by-step explanation:
The horizontal leg is 0, since there is no horizontal component of the triangle, so, the cosine is 0. Consider the angle itself and the unit circle. There is no horizontal component of the angle: The horizontal component of the angle is 0, so, the cosine of 90° is 0.
Answer:
OXY=18
Step-by-step explanation:
The ratio of AABC to AAXY is 4:3 so the lengths will be in that ratio too. The ratio of BC:XY is 4:3. BC is 24 so 24:XY is 4:3. You need to divide 24 by 6 to get 4 so multiply 3 by 6 to get the answer 18.