The only way 3 digits can have product 24 is
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4
To be divisible by 3 the sum of the digits must be divisible by 3.
1+ 3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3.
So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.
Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.
The others must end in 3.
They must be greater than 152 which is 225. So the
First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.
The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
I think I got it, but just in case...tell me the whole thing again. I wasn't listening.
The shape looks like a box with a chunk taken out of it. So, to find the volume of the shape, let us find the volume of the hypothetical "perfect" box and then subtract the volume of the chunk.
Volume of the box = 15x6x12 = 1080 cm³
Volume of the chunk = 10x6x4 = 240 cm³
Volume of weird shape = 1080-240 = 840 cm³
Answer: 840 cm³
1g=16c
16g=X
X=256
I really hope that helped
Answer: B
Step-by-step explanation:
These are vertical angles, so x+97=2x+32, meaning x=65.
So, the measure of angle 1 = 65 + 97 = 162 degrees
