Question

In 1970, a farmer using a two-row combine with a corn head could easily harvest 0.75 ha (1.85 acres) per hour and a typical corn yield was 5000 kg/ha (80 bu/acre). Before 1940, most corn was harvested by hand and a skilled person could harvest 250 kg/h (10 bu/h). Calculate the productivity ratio.

Answer 1

Answer:

The value is $w = 6.7 \%$

Step-by-step explanation:

Generally the productivity rate is mathematically represented as

$P_r = K * Z$

Here K is the ha the farmer could harvest in an hour and Z is a typical yield of corn in kg/ha

Now considering 1970

The productivity rate is

$P_r = 0.75 *5000$

=> $P_r = 3750 \ kg/h$

Now considering 1940

The productivity rate is given as $P_R = 250 \ kg/h$

Generally the productivity ratio is mathematically ration is mathematically represented as

$w = \frac{P_R}{P_r} * 100$

=> $w = \frac{250}{3750} * 100$

=> $w = 6.7 \%$