Answer:
the function is continuous from the left at x=1 and continuous from the right at x=0
Step-by-step explanation:
a function is continuous from the right , when
when x→a⁺ lim f(x)=f(a)
and from the left when
when x→a⁻ lim f(x)=f(a)
then since the functions presented are continuous , we have to look for discontinuities only when the functions change
for x=0
when x→0⁺ lim f(x)=lim e^x = e^0 = 1
when x→0⁻ lim f(x)=lim (x+4) = (0+4) = 4
then since f(0) = e^0=1 , the function is continuous from the right at x=0
for x=1
when x→1⁺ lim f(x)=lim (8-x) = (8-0) = 8
when x→1⁻ lim f(x)=lim e^x = e^1 = e
then since f(1) = e^1=e , the function is continuous from the left at x=1
Here are table and graph on the same page.
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The parent absolute value function is expanded vertically by a factor of 2, then translated right 4 units and up 3 units.
=12, I think, can I have Brainly
multiply 500 by 4 to know how much is needed in grams first
500×4 = 2000
convert 2000grams to kilograms
since 1000grams make 1 kilograms....then divide 2000 by 1000
which would give you 2000/1000
answer = 2kg of sugar
