Answer:
Step-by-step explanation:
Hello!
The study variable is:
X: number of customers that recognize a new product out of 120.
There are two possible recordable outcomes for this variable, the customer can either "recognize the new product" or " don't recognize the new product". The number of trials is fixed, assuming that each customer is independent of the others and the probability of success is the same for all customers, p= 0.6, then we can say this variable has a binomial distribution.
The sample proportion obtained is:
p'= 54/120= 0.45
Considering that the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample proportion to normal: p' ≈ N(p;
)
The other conditions for this approximation are also met: (n*p)≥5 and (n*q)≥5
The probability of getting the calculated sample proportion, or lower is:
P(X≤0.45)= P(Z≤
)= P(Z≤-3.35)= 0.000
This type of problem is for the sample proportion.
I hope this helps!
Are you seriously asking that? 4.25 - 2.75. 1.5 is the answer
The answer to Part A is 13.25.
And the answer to Part B is hen you round to the nearest 10th the steps are nearly always the same:<span>Identify which place value you are rounding to. The smaller the place value, the more accurate the final result will be.Look to the next smallest place value, the digit to the right of the place value you're rounding to. For example, if you want to round to the nearest ten you'd look at the ones place.If the digit in the next smallest place value is less than five (0, 1, 2, 3, or 4), you leave the digit you want to round to as-is. Any digits after that number (including the next smallest place value you just looked at) become zeros, or drop-off if they're located after the decimal point. This is called rounding down.<span>If the next smallest place value is greater than or equal to five (5, 6, 7, 8, or 9), you increase the value of the digit you're rounding to by one (+1). Just like before, any remaining digits before the decimal point become zeros, and any that are after the decimal point are dropped. This is called rounding up.
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Answer:
93.75 Kg
Step-by-step explanation:
Farmer spreads 25 kg fertilizer over an area of 4000 m square .
So, Over 1 m square ,
kg of fertilizer will be needed
As we know , 1 hectare = 10,000 m square.
So, 1.5 hectare equals 15,000 m square.
So, for 15,000 m square , Fertilizer needed will be equal to
×15,000 = 93.75 Kg
So, 93.75 Kg of fertilizer is needed for 1.5 ha of land.