18. The perimeter is simply √3 + √3 + √3 + √3 or 4√3cm, since the perimeter is just all sides added together. You could add the decimal numbers together using a calculator, which I'm not sure if you're supposed to do in your class.
The area is just width times length, so √3 • √3 = 3cm².
19. The perimeter is 2√5 + 2(9 - √5).
This can also be written as 2√5 + 18 - 2√5, which leaves you with a perimeter of 18ft.
The area would be √5 • (9 - √5), which leaves you with (9√5 - 5)ft².
20. The formula for the perimeter (or circumference) of a circle is π times the diameter of the circle. Using the radius of the circle, 1/π, the diameter is 2/π, so
π • 2/π = 2. The circumference of the circle is 2 inches.
The area of the circle is calculated with the equation πr², so
π(1/π)² = π • 1/(π²) = π/(π²) = π. The area is simply π in².
Answer:
A
Step-by-step explanation:
We have the expression 
We want to find the value when k is -3. So, substitute -3 for k and evaluate:
Multiply:
Subtract:
Add:
Therefore, our answer is A.
<span>Line ET is tangent to circle A at T
</span>
∴ ET ⊥ TN
∴ ∠ ETN = 90
<span>the measure of Arc TG = 70
</span>
∠ TNG = half <span>the measure of Arc TG = 0.5 *70 = 35
</span>
<span>Δ ETN ⇒ The sum of all angles = 180
</span>
<span>∴∠ GET = ∠ NET = 180 - (90 + 35 ) = 55
</span>
∴ The correct answer is option <span>A. 55°</span>
-9x+2y = -36
when x=0 ; 2y = -36
so y = -18
then y-intercept(x=0) is -18
I think that the fencing is needed
