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pishuonlain [190]
3 years ago
8

Please help me please please please!!!​

Mathematics
1 answer:
Leni [432]3 years ago
4 0

Answer:Yes both the triangles are congruent because all three sides are equal.

Step-by-step explanation:

And for the values of x and y we should equate by putting side AB=FD and side BC=ED.

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Two different sizes of square metal duct are joined by a piece that is a frustum of a pyramid. Find the lateral surface area, if
Allisa [31]

Answer:

288 in²

Step-by-step explanation:

The formula used to solve this question is :

Lateral Surface Area = s( P1 + P2)

Where s = slant height = 2 inches

P1 and P2 = Perimeter of the bases

Perimeter of base 1 = 4 × length of the end of the small square

4 × 17 inches = 68 inches

Perimeter of base 2 = 4 × length of the end of the large square

4 × 19 inches = 76 inches

Lateral Surface Area = 2 × (68 + 76)

= 2 × 144

= 288 in²

8 0
3 years ago
What is the product of and (6+5i) and (3-7i) ?<br><br> -17-27i<br> -17+27i<br> 53+27i<br> 53-27i
USPshnik [31]
We are going to make the product step by step.
 We have:
 (6 + 5i) * (3-7i)
 Multiplying:
 ((6) * (3)) + ((6) * (- 7i)) + ((5i) * (3)) + ((5i) * (- 7i))
 Rewriting:
 18 - 42i + 15i - 35i ^ 2
 18 - 42i + 15i - 35 * (- 1)
 18 - 42i + 15i + 35
 53 - 27i
 Answer:
 
the product of and (6 + 5i) and (3-7i) is:
 
53-27i
5 0
3 years ago
Find the perimeter of ABC with vertices A(0,-4), B(4,-4), and C(0,-1).
Vesna [10]
<span>you know the measure of AC that is 4 and the measure of AB that is 4. Then you do the theorem of Pythagoras 4 squared + 4 squared = hypotnuza (CB)
</span>
then + all sides
6 0
3 years ago
Which translation vectors could have been used for the pair of figures?
Ierofanga [76]

if set up like

1 2

3 4

5 6

it would be 4 and 6

7 0
3 years ago
Read 2 more answers
Please help and if you can please explain it well thank you
Ksju [112]

Answer:

there is a feature on this app where u can take a picture and it will give u the answer. i would suggest trying that because it is quite useful

4 0
3 years ago
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