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Mariulka [41]
3 years ago
6

^^ question above! Thanks!

Mathematics
1 answer:
IceJOKER [234]3 years ago
8 0
7 square root 2
Maybe this will help
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If mZDCB = 140°, then mZACD = [?]° !!!PLS HELP I WILL MARK BRAINLIEST !!!
Readme [11.4K]

Answer:

40°

Step-by-step explanation:

  • m\angle DCB +m\angle ACD = 180\degree (Linear pair angles)

  • \implies 140\degree +m\angle ACD = 180\degree

  • \implies m\angle ACD = 180\degree-140\degree

  • \implies m\angle ACD = 40\degree
5 0
2 years ago
This graph shows a proportional relationship.
Nonamiya [84]
Not quite sure but:
2/3 = 3/4
divide all by 2/3 to get a 1 value so
1 = 0.8
4 0
3 years ago
Read 2 more answers
What is two decimal that are equivalent to 7.06
ycow [4]

Answer:7.060 and 7.0600


Step-by-step explanation:0 doest not mean nothing


4 0
3 years ago
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Evaluate sin(36°), round your answer to four decimal places.
Mrrafil [7]

Answer:

sin(36^{\circ})=\approx 0.5878

Step-by-step explanation:

We are given that

sin(36^{\circ)

We have to find the value of sin(36^{\circ)

To find the value of sin(36^{\circ)  we will use table of sin

From sin table

We get

sin(36^{\circ})

=0.587785

We have to round off the answer to four decimal places

Therefore,

sin(36^{\circ})=\approx 0.5878

7 0
3 years ago
I need help on numbers 11-16
agasfer [191]
Recall your SOH CAH TOA, or \bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}

now, bear in mind that, the opposite side, to an angle, is the side right "in front of it", that is, if you were to put your eye on that angle, "the wall" you'd see on the other end, is the opposite side

the adjacent side, adjacent = next to, is the side that's touching the angle itself

and the hypotenuse, is always the slanted and longest side of all three

for example on 16, tangent of Z

if you put one eye on Z, you'll see on the other end, the side of 30 units
the adjacent side is the one touching Z, or the 40 units side

\bf tan(\theta)=\cfrac{opposite}{adjacent}\implies tan(Z)=\cfrac{30}{40}
\\\\\\
\textit{which can be simplified to }\cfrac{3}{4}


and you'd do all others, the same way, using those ratios

use \bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
8 0
3 years ago
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