The number of interceptions made by a defensive back is definitely countable because it is finite and also it is not continuous because each interception is different and is unique. That is to say, one interruption happens and then then next. They do not happen in a continuous manner.
Thus, the number of interceptions made by a defensive back are countable and are discrete. Having a look at the options we can see that Option C matches as it says "the variable is discrete because it is countable".
Thus Option C is the answer.
If it is hexagon, 6 sides
1 side = 3x+5
6 sides = 6(3x+5)
perimeter
18x + 30
We obtain the joint PMF directly from the joint MGF:
![\implies\mathrm{Pr}[X=x,Y=y]=\begin{cases}0.1&\text{for }x=y=0\\0.2&\text{for }x=1,y=0\\0.3&\text{for }x=0,y=1\\0.4&\text{for }x=y=1\\0&\text{otherwise}\end{cases}](https://tex.z-dn.net/?f=%5Cimplies%5Cmathrm%7BPr%7D%5BX%3Dx%2CY%3Dy%5D%3D%5Cbegin%7Bcases%7D0.1%26%5Ctext%7Bfor%20%7Dx%3Dy%3D0%5C%5C0.2%26%5Ctext%7Bfor%20%7Dx%3D1%2Cy%3D0%5C%5C0.3%26%5Ctext%7Bfor%20%7Dx%3D0%2Cy%3D1%5C%5C0.4%26%5Ctext%7Bfor%20%7Dx%3Dy%3D1%5C%5C0%26%5Ctext%7Botherwise%7D%5Cend%7Bcases%7D)
Then
![\mathrm{Pr}[X=Y]=\mathrm{Pr}[X=Y=0]+\mathrm{Pr}[X=Y=1]=0.1+0.4=\boxed{0.5}](https://tex.z-dn.net/?f=%5Cmathrm%7BPr%7D%5BX%3DY%5D%3D%5Cmathrm%7BPr%7D%5BX%3DY%3D0%5D%2B%5Cmathrm%7BPr%7D%5BX%3DY%3D1%5D%3D0.1%2B0.4%3D%5Cboxed%7B0.5%7D)
Answer:
grams
Step-by-step explanation:
Given
Required
Determine the mass of 401,000,000 electrons
To do this, we simply multiply the mass of 1 electron by the number of electrons.
This gives:
Express 3653110000 as a standard form
Apply law of indices:
Hence, the mass of 401000000 electrons is 
