Answer:
49m/s
59.07 m/s
Step-by-step explanation:
Given that :
Distance (s) = 178 m
Acceleration due to gravity (a) = g(downward) = 9.8m/s²
Velocity (V) after 5 seconds ;
The initial velocity (u) = 0
Using the relation :
v = u + at
Where ; t = Time = 5 seconds ; a = 9.8m/s²
v = 0 + 9.8(5)
v = 0 + 49
V = 49 m/s
Hence, velocity after 5 seconds = 49m/s
b) How fast is the ball traveling when it hits the ground?
V² = u² + 2as
Where s = height = 178m
V² = 0 + 2(9.8)(178)
V² = 0 + 3488.8
V² = 3488.8
V = √3488.8
V = 59.07 m/s
Answer:
D. A sequence with 5 terms that starts with 3 and has a common ratio of 2
Answer:
h = - 105
Step-by-step explanation:
Given
= - 7.5 ( multiply both sides by 14 to clear the fraction )
h = - 105
Answer:

Step-by-step explanation:
The standard form of a quadratic is
. You need to subtract the x^2 from the right to set the quadratic equal to 0. Then a,b, and c are equal to the values of the coefficients in front of the terms.
If this helped, a brainliest would be greatly appreciated!
Answer:
24 i'm pretty sure sorry if i am wrong
Step-by-step explanation: