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Makovka662 [10]

3 years ago

9

What is the perimeter of a regular octagon in which all sides have a length of 5 feet.

2 answers:

Lunna [17]3 years ago

7 0

Perimeter = sum of all the sides.
A regular octagon has<em> </em><u><em>8 sides</em></u><em />.
The length of <em>each side </em>= 5 ft.
One side = 5 ft.
Eight sides = 5 × 8 = 40 ft.

The perimeter of the octagon is <u><em>40 ft.</em></u>

sineoko [7]3 years ago

5 0

Octagons have 8 sides. If each side is 5 feet then the perimeter is 40 feet. You add up the sides.

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Drag the tiles to the correct boxes to complete the pairs.Not all tiles will be used match the equations representing parabolas

IceJOKER [234]

Answer:

$y=-8.08$ -------> $y+8=3(x+2)^{2}$

$y=14.25$ -------> $y-14=-(x-3)^{2}$

$y=-7.625$ -----> $y+7.5=2(x+2.5)^{2}$

$y=17.25$ -------> $y-17=-(x-3)^{2}$

$y=-7.25$ -------> $y+7=(x-4)^{2}$

$y=6.25$ -------> $y-6=-(x-1)^{2}$

Step-by-step explanation:

we know that

The standard form of a vertical parabola is equal to

$(x-h)^{2}=4p(y- k)$

where

(h,k) is the vertex

the focus is (h, k + p)

and

the directrix is y = k - p

Part 1) we have

$y+8=3(x+2)^{2}$

Convert to standard form

$(x+2)^{2}=(1/3)(y+8)$

The vertex is the point $(-2,-8)$

$h=-2,k=-8$

$4p=1/3$

$p=1/12$

the directrix is equal to

$y = k-p$ -----> $y=-8-(1/12)=-8.08$

Part 2) we have

$y-14=-(x-3)^{2}$

Convert to standard form

$(x-3)^{2}=-(y-14)$

The vertex is the point $(3,14)$

$h=3,k=14$

$4p=-1$

$p=-1/4$

the directrix is equal to

$y = k-p$ -----> $y = 14-(-1/4)=14.25$

Part 3) we have

$y+7.5=2(x+2.5)^{2}$

Convert to standard form

$(x+2.5)^{2}=(1/2)(y+7.5)$

The vertex is the point $(-2.5,-7.5)$

$h=-2.5,k=-7.5$

$4p=1/2$

$p=1/8$

the directrix is equal to

$y = k-p$ -----> $y=-7.5-(1/8)=-7.625$

Part 4) we have

$y-17=-(x-3)^{2}$

Convert to standard form

$(x-3)^{2}=-(y-17)$

The vertex is the point $(3,17)$

$h=3,k=17$

$4p=-1$

$p=-1/4$

the directrix is equal to

$y = k-p$ -----> $y = 17-(-1/4)=17.25$

Part 5) we have

$y+7=(x-4)^{2}$

Convert to standard form

$(x-4)^{2}=(y+7)$

The vertex is the point $(4,-7)$

$h=4,k=-7$

$4p=1$

$p=1/4$

the directrix is equal to

$y = k-p$ -----> $y=-7-(1/4)=-7.25$

Part 6) we have

$y-6=-(x-1)^{2}$

Convert to standard form

$(x-1)^{2}=-(y-6)$

The vertex is the point $(1,6)$

$h=1,k=6$

$4p=-1$

$p=-1/4$

the directrix is equal to

$y = k-p$ -----> $y=6-(-1/4)=6.25$

4 0

3 years ago

Aaron bought a new TV for $1,224. He is paying it off over a period of 12 months. How much will Aaron pay per month for his new

boyakko [2]

1224 / 12 = 102

He will be paying $102 a month for his TV

3 0

3 years ago

Read 2 more answers

What is the inverse function? Can any math experts help please

kaheart [24]

Answer:

f^-1(x) = (4x + 3)^2

8 0

3 years ago

Read 2 more answers

jeka94

The exact circumference of the circle is $7 \frac{49}{150} k m$

The approximate circumference of the circle is $7.33 k m$

Explanation:

The diameter of the circle is $2 \frac{1}{3} \mathrm{km}$

Now, we shall find the circumference of the circle.

The formula to determine the circumference of the circle is given by

$C=\pi d$

Where C is the circumference , $\pi$ is 3.14 and $d=2 \frac{1}{3} \mathrm$ is the diameter of the circle.

The exact circumference of the circle is given by

$\begin{aligned}C &=\pi d \\&=(3.14)\left(2 \frac{1}{3}\right) \\&=(3.14)\left(\frac{7}{3}\right) \\&=\frac{21.98}{3}\end{aligned}$

Multiply both numerator and denominator by 100, we get,

$C=\frac{2198}{300} \\C=\frac{1099}{150}$

Converting $\frac{1099}{150}$ into mixed fraction, we get,

$C=7 \frac{49}{150}$

Thus, the exact circumference of the circle is $7 \frac{49}{150} k m$

The approximate value of the circumference can be determined by dividing the value $\frac{1099}{150}$

$C=\frac{1099}{150}=7.327$

$C=7.33km$

Thus, the approximate circumference of the circle is $7.33 k m$

3 0

3 years ago

Is a parallelogram always a square?<br> yes<br> no

polet [3.4K]

Answer:

yes

Step-by-step explanation:

4 0

3 years ago