Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
Answer:
0.683
Step-by-step explanation:
We have to find P(-1<z<1).
For this purpose, we use normal distribution area table
P(-1<z<1)=P(-1<z<0)+(0<z<1)
Using normal area table and looking the value corresponds to 1.0, we get
P(-1<z<1)=0.3413+0.3413
P(-1<z<1)=0.6826
Rounding the answer to three decimal places
P(-1<z<1)=0.683
So, 68.3% of the z-scores will be between -1 an 1.
Answer:
Side lengths = 15 ft²
Step-by-step explanation:
Given:
Area of square = 255 ft²
Find:
Side lengths
Computation:
Area of square = side x side
Area of square = 255 ft²
Side lengths = √Area of square
Side lengths = √255
Side lengths = 15 ft²
1. She earns 300 dollars an hour
2. He will be paid 180 dollars
3. She pays 26,150 dollars
