Question

2 questions ples answer

Answer 1

1. We are given:
$a^2 = 64$

The only a which squared gives you 64 is 8. The perimeter of an 8 by 8 square will be 32. Half of that is 16. Now, let's see what we can do. We can set up:
$4a = 16$

Obviously, each side length has to be 4. So, the area of this square will be 16 units².

2. Let n equal her son's age. So, her age right now will be (S = her age):
$S = 18n$
1 year ago it was:
$S-1 = 3n$

We have 2 equations, let's substitute. We can rewrite this as:
$18n-1 = 3n$
Solve for n:
$15n-1=0$
$n= \frac{1}{15}$

We know the value of n, which is her son's age. So, her son is 1/15 of a year old or about 24 days old.