Answer:
0.665
Step-by-step explanation:
Given: 100 people are split into two groups 70 and 30. I group is given cough syrup treatment but second group did not.
Prob for a person to be in the cough medication group = 0.70
Out of people who received medication, 34% did not have cough
Prob for a person to be in cough medication and did not have cough
=
Prob for a person to be not in cough medication and did not have cough
=
Probability for a person not to have cough
= P(M1C')+P(M2C')
where M1 = event of having medication and M2 = not having medication and C' not having cough
This is because M1 and M2 are mutually exclusive and exhaustive
SO P(C') = 0.397+0.2=0.597
Hence required prob =P(M1/C') = 
Answer:
6c³
Step-by-step explanation:
18c³ = 2 × 3 × 3 × c × c × c
24c³ = 2 × 2 × 2 × 3 × c × c × c
Now we show the common factors in bold:
18c³ = 2 × 3 × 3 × c × c × c
24c³ = 2 × 2 × 2 × 3 × c × c × c
The common factor are:
2, 3, c, c, c
GCF = 2 × 3 × c × c × c = 6c³
(-9, -1)
(-9,-1) . -1 because that is the y intercept from the equation.
-9 because when you substitute -2 for x, and multiply by 4, you get -8. Then you subtract one, making the x value -9.
Therefore, the ordered pair of the solution is (-9,-1)
Hope this helps, please consider marking branliest if it did.
Answer:
P = 0.05
Step-by-step explanation:
12 months * 30 days each = 360 days
From 306 days, we have to select 8 days = 360C8 ways(Total ways)
We want each days from different month. First, we have to select 8 month from 12 month = 12C8 ways
---By selecting 8 month, we will select a days from each month. That can be done in = 30C1 * 30C1 * .................30C1 (8 ways) [From a month with 30 days, we can select a day in 30C1 ways = 30 ways]
Therefore P = Number of ways of selecting each days from different month / Total number of ways
P = 12C8 * 30^8 / 360C8
P = 495 * 656100000000 / 6469697679132645
P = 0.0501985588982791
P = 0.05
Hence the probability that each day is from a different month is 0.05
