Question

A curve passes through the point (0, 5) and has the property that the slope of the curve at every point P is twice the y-coordinate of P. What is the equation of the curve? (Use x as the independent variable.

Answer 1

Answer:

$y=5e^{2x}$

Step-by-step explanation:

Let (x,y) represents a point P on the curve,

So, the slope of the curve at point P = $\frac{dy}{dx}$

According to the question,

$\frac{dy}{dx}=2y$

$\frac{1}{y}dy=2dx$

Integrating both sides,

$\int \frac{dy}{y}=2dx$

$ln y=2x+ln C$

$ln y-ln C = 2x$

$ln(\frac{y}{C})=2x$

$\frac{y}{C}=e^{2x}$

$\implies y=Ce^{2x}$

Since, the curve is passing through the point (0, 5),

$5=Ce^{0}\implies C=5$

Hence, the required equation of the curve is,

$y=5e^{2x}$