X-2y=-12
x+6y=20
we can cancel x's
multiply first equation by -1 and add to 2nd equation
-x+2y=12
<u>x+6y=20 +</u>
0x+8y=32
8y=32
divide both sides by 8
y=4
sub back
x-2y=-12
x-2(4)=-12
x-8=-12
add 12 both sides
x=-4
(x,y)
(-4,4)
2(3x + 4) / 2(2x + 2)
Cancel the factored 2s
3x + 4 / 2x + 2
You may need to further factor the denominator, depending on the teacher.
3x + 4 / 2(x + 1)
Two circles<span> of </span>radius<span> 4 are </span>tangent<span> to the </span>graph<span> of y^</span>2<span> = </span>4x<span> at the </span>point<span> (</span>1<span>, </span>2<span>). ... I know how to </span>find<span> the </span>tangent<span> line from a circle and a given </span>point<span>, but ... </span>2a2=42. a2=8. a=±2√2. Then1−xc=±2√2<span> and </span>2−yc=±2√2. ... 4 from (1,2<span>), so you could </span>find these<span> centers, and from there the</span>equations<span> of the circle
</span>
Answer:
6.4
Step-by-step explanation:
