Answer:
Step-by-step explanation:
Area is the product of two dimensions.
<u>If the scale factor is 1/4, the ratio of the areas will be: </u>
The smaller prism has a surface are of 45 cm².
<u>The larger prism has a surface area:</u>
The value of x when y = 14 is 8.4
<h3 />
<h3>How to solve variation ?</h3>
y, varies directly as x. Therefore,
y ∝ x
Therefore,
y = kx
where
- k =constant of proportionality
Therefore,
10 = 6k
k = 10 / 6
k = 5 / 3
Hence, when y = 14
y = kx
14 = 5 / 3 x
cross multiply
42 = 5x
x = 42 / 5
x = 8.4
learn more on variation here: brainly.com/question/20707320
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sin^2 x + 4 sinx +3 3 + sinx
-------------------------- = -------------------
cos^2 x 1 - sinx
factor the numerator
(sinx +3) (sinx+1) 3 + sinx
-------------------------- = -------------------
cos^2 x 1 - sinx
cos^2 = 1-sin^2x
(sinx +3) (sinx+1) 3 + sinx
-------------------------- = -------------------
1- sin^2x 1 - sinx
factor the denominator
(sinx +3) (sinx+1) 3 + sinx
-------------------------- = -------------------
(1-sinx ) (1+sinx) 1 - sinx
cancel the common term (1+sinx) and (sinx +1)
(sinx +3) 3 + sinx
-------------------------- = -------------------
(1-sinx ) 1 - sinx
reorder the first term
3+sinx 3 + sinx
-------------------------- = -------------------
(1-sinx ) 1 - sinx
<span>1. How much heat is absorbed by a 50g iron skillet when its temperature rises from 10oC to 124oC? Joules
Formula: Heat = mass * specific heat * ΔT
Data:
mass = 50 g = 0.050 kg
specific heat of iron = 450 J/ kg °C
ΔT = 124°C - 10°C ¿ 114 °C
=> heat = 0.050kg * 450 J / kg°C * 114°C ≈ 2.6 J
2. If a refrigerator is a heat pump that follows the first law of
thermodynamics, how much heat was removed from food inside of the
refrigerator if it released 492J of energy to the room? Joules
The firs law of thermodynamics is conservation of energy => energy removed from inside of the refrigerator = energy released to the room
=> Answer = 492 J
3. How much heat is needed to raise the temperature of 45g of water by 63oC? Joules
Formula: heat = mass * specific heat * ΔT
specific heat of water = 4186 J / Kg °C
heat = 0.045 kg * 4186 J/kg °C * 63°C = 11,867.31 J
</span>
Answer:
-5 2/3
Step-by-step explanation:
is 3(x-2) = -7 then it's same as 3x-6=-7
We simplify this by adding 6 and subtracting 6.
Our result is
3x=-17
-17/3=-5 2/3
