I’m sorry if I’m wrong but I do think your answer is X=22y^-1
One is 17.22 and the other is simply 2.
P(t)=6t
A(p)=πp^2, since p(t)=6t
A(t)=π(p(t))^2
A(t)=π(6t)^2
A(t)=36πt^2, so when t=8 and approximating π≈3.14
A(8)≈36(3.14)(8^2)
A(8)≈36(3.14)64
A(8)≈7234.56 u^2
Answer:
5, 3
Step-by-step explanation:
correct on edge2020
