Y=-1/2x+10x what is the height of the arch at the turning point

A rectangular box has length 20cm, width 6cm and height 4cm. find how many cubes of size 2cm that will fit into the box.

Papessa [141]

Answer:

$\boxed{\pink{\sf The \ number \ of \ cubes \ that \ can \ be \ fitted \ is 60 .}}$

Step-by-step explanation:

Given dimensions of the box = 20cm × 6cm × 4cm .

Dimension of the cube = 2cm × 2cm × 2cm .

Therefore the number of cubes that can be fitted into the box will be equal to the Volume of box divided by the Volume of the cube. So ,

$\boxed{\red{\bf \implies No. \ of \ cubes \ = \dfrac{Volume \ of \ box}{Volume \ of \ cube }}}$

$\bf \implies n_{cubes} = \dfrac{20cm \times 6cm \times 4cm .}{2cm \times 2cm \times 2cm } \\\\\bf\implies n_{cubes} = 10 \ times 3cm \times 2cm \\\\\implies \boxed{\bf n_{cubes}= 60 }$

<h3>Hence the number of cubes that can be fitted in the box is 60 .</h3>

6 0

3 years ago

1. A length of rope is stretched between the top edge of a building and a stake in the ground. The head of the stake is at groun

denpristay [2]

Answer:

19

Step-by-step explanation:

4 0

2 years ago

For an angle θ, tan(θ) is a negative number. Which quadrants might θ be in?

Klio2033 [76]

So for this question, we're asked to find the quadrant in which the angle of data lies and were given to conditions were given. Sign of data is less than zero, and we're given that tangent of data is also less than zero. Now I have an acronym to remember which Trig functions air positive in each quadrant. . And in the first quadrant we have that all the trig functions are positive. In the second quadrant, we have that sign and co seeking are positive. And the third quadrant we have tangent and co tangent are positive. And in the final quadrant, Fourth Quadrant we have co sign and seeking are positive. So our first condition says the sign of data is less than zero. Of course, that means it's negative, so it cannot be quadrant one or quadrant two. It can't be those because here in Quadrant one, we have that all the trick functions air positive and the second quadrant we have that sign. If data is a positive, so we're between Squadron three and quadrant four now. The second condition says the tangent of data is also less than zero now in Quadrant three. We have that tangent of data is positive, so it cannot be quadrant three, so our r final answer is quadrant four, where co sign and seek in are positive.

4 0

2 years ago

Read 2 more answers

You and a friend or 2 pizzas from pizza hut. you ate 7/8 of one pizza and 3/4 of the other pizza. find the product of the amount

kotegsom [21]

13/8 or 1 5/8
3/4 becomes 7/8 when add it is 13/8

6 0

3 years ago

Somebody please help me thansk

ad-work [718]

Answer:

y=-2x-1