Question

N a dihybrid cross for round and yellow seeds (RrYy x RrYy), what is the probability of having green and wrinkled seeds?

Answer 1

Answer:

1/16

Explanation:

See the Punnett square diagram to observe the result of the cross between the round and yellow plants (RrYy X RrYy).

Since round (R) is dominant over wrinkled (r) and yellow (Y) is dominant over y (green), the plant with genotype rryy would have wrinkled and green phenotype as these are recessive characters.

From the given cross in the Punnett square, we can observe that there is a total of 16 possible progenies and out of these only 1 has the wrinkled and green phenotype.

Therefore the probability is 1/16.

Answer 2

The question is asking to choose among the following question that states the probability of having green and wrinkled seeds and base on the given data, I would say that the ratio would be 1:16. hope this helped out!!!!