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Margarita [4]
3 years ago
9

Need help fast please! Factor by grouping. 6x³ + 24x² -7x -28 =

Mathematics
1 answer:
olchik [2.2K]3 years ago
5 0

Answer:

(x+4)(6x^2 - 7)

Step-by-step explanation:

Focus on the first 2 terms first and on the second 2 terms last:

6x^3 + 24x^2 = 6x^2(x+4)

-7x-28 = -7(x+4)

We see that the factor (x+4) is common to both pairs:  common to the first 2 terms and common to the last 2 terms.

Thus,

6x³ + 24x² -7x -28 = (x+4)(6x^2 - 7(x+4)

Factoring out x+4, we get (6x^2 - 7), and so 6x³ + 24x² -7x -28 in factored form is (x+4)(6x^2 - 7).

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Answer: 2 then 1

Step-by-step explanation:

Just did it

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3 years ago
If y = (x-5)(x+7) then what does x equal?
DochEvi [55]

Answer:

x = 5, x = -7

Step-by-step explanation:

If you mean find the roots, then x = 5 and x = -7

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3 years ago
(GIVING BRAINLIEST AND 15 POINTS FOR ANSWER) Solve five and three sixths minus two and one third.
a_sh-v [17]

Answer:

three and three eighteenths

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2 years ago
The length of a rectangle is increasing at a rate of 4 meters per day and the width is increasing at a rate of 1 meter per day.
puteri [66]

Answer:

\displaystyle \frac{dA}{dt} = 102 \ m^2/day

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Geometry</u>

Area of a Rectangle: A = lw

  • l is length
  • w is width

<u>Calculus</u>

Derivatives

Derivative Notation

Implicit Differentiation

Differentiation with respect to time

Derivative Rule [Product Rule]:                                                                              \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle l = 10 \ meters<u />

<u />\displaystyle \frac{dl}{dt} = 4 \ m/day<u />

<u />\displaystyle w = 23 \ meters<u />

<u />\displaystyle \frac{dw}{dt} = 1 \ m/day<u />

<u />

<u>Step 2: Differentiate</u>

  1. [Area of Rectangle] Product Rule:                                                                 \displaystyle \frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}

<u>Step 3: Solve</u>

  1. [Rate] Substitute in variables [Derivative]:                                                    \displaystyle \frac{dA}{dt} = (10 \ m)(1 \ m/day) + (23 \ m)(4 \ m/day)
  2. [Rate] Multiply:                                                                                                \displaystyle \frac{dA}{dt} = 10 \ m^2/day + 92 \ m^2/day
  3. [Rate] Add:                                                                                                      \displaystyle \frac{dA}{dt} = 102 \ m^2/day

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Implicit Differentiation

Book: College Calculus 10e

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Ahat [919]

Answer:

10 is the answer hope this helps :)

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