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KATRIN_1 [288]
3 years ago
5

The total cost to stay one night at sleepyhead motel is $119 without breakfast and $124 with breakfast included what is the diff

erence in the cost for a one night stay with and without breakfast
Mathematics
2 answers:
Inessa05 [86]3 years ago
6 0

Cost to stay one night at Sleepyhead Motel without breakfast = $119

Cost to stay one night at Sleepyhead Motel with breakfast = $124

⇒ Difference in the cost for a one night stay with and without breakfast  = Cost to stay one night at Sleepyhead Motel with breakfast - Cost to stay one night at Sleepyhead Motel without breakfast

⇒ Difference in the cost for a one night stay with and without breakfast  = $124 - $119

⇒ Difference in the cost for a one night stay with and without breakfast  = $5

maria [59]3 years ago
4 0

The total cost to stay one night at sleepyhead motel without breakfast =  $119

The total cost to stay one night at sleepyhead motel with breakfast =  $124

We have to find the difference in the cost for a one night stay with and without breakfast.

Difference = $124 - $119

= $5

Therefore, the difference in the cost for a one night stay with and without breakfast is $5.

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3 years ago
What is the width of this shape
77julia77 [94]
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Think of it this way:
A = l*w

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And w is what we're looking for.
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3 years ago
The points A BC :(2, 2,1), :(1,1,3), :(2,0,5) − are the vertices of a right triangle. The radius of the sphere with center at th
ElenaW [278]

Answer:

r=1

Step-by-step explanation:

First we need to know the length of each side of the triangle, so we use the formula of the vector modulus:

|AB|= \sqrt{(b_{1}-a_{1})^{2}+(b_{2}-a_{2})^{2}+(b_{3}-a_{3})^{2}

By doing so, we find:

|AB|=\sqrt {6}\\|BC|=\sqrt {6}\\|AC|=2\sqrt {5}

With this we know that the triangle is not right, but, we assume the longest side as the hypotenuse of the problem.

As we have two equal sides, we know that the line between point |AB| and the center of the hypotenuse is perpendicular, therefore, we can calculate it using Pythagoras theorem:

|BC|^{2}=r^{2}+(\frac{|AC|}{2})^{2}\\\\r^{2}=|BC|^{2}-(\frac{|AC|}{2})^{2}\\\\r^{2}=(\sqrt{6})^{2}- (\frac{2\sqrt{5}}{2})^{2}\\\\r^{2}=6-5=1\\r=1

4 0
3 years ago
Find the equation of the line that is parallel to 3x-4y=6 and passes through the point (-12,10)
horsena [70]
Answer:

y = 3/4x + 19

Explanation:

First we need to write the equation in the form y=mx+c:

3x-4y=6
-4y=-3x+6
y=3/4x-3/2

Because the lines are parallel, we can deduce that the gradients (m) are equal. That means that the gradient of our new equation will also be 3/4.

We will now use the following equation:

y - y1 = m(x - x1)

We will substitute in the new line’s gradient as well as the coordinates we were given:

y - 10 = 3/4(x + 12)

Now we solve this equation into the form y=mx+c:

y - 10 = 3/4x + 9
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5 0
3 years ago
Read 2 more answers
Help me wegnerkolmp2741o
Pie

Answer:

Step-by-step explanation:

All these amount of money are based on Dan's initial amount, which is x. Ben had 7 more than Dan, so Ben's amount of money is x + 7. Kaden has 4 more than Ben, so Kaden's amount of money is 4 + (x + 7) which is x + 11. So here's the breakdown so far:

Dan: x

Ben: x + 7

Kaden: x + 11

Now it looks like Kaden is the favorite and got another 20 from his mom, so his amount became x + 31. After Dan spends a dollar, making his amount x - 1, Kaden had 9 times what Dan had. Now we have finally:

x + 31 = 9(x - 1) and

x + 31 = 9x - 9 and

40 = 8x so

x = 5.

Dan originally had $5, Ben originally had $12, and Kaden originally had $16

8 0
3 years ago
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