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dexar [7]
3 years ago
13

HELP PLEASE!!

Mathematics
2 answers:
Harman [31]3 years ago
7 0

Answer:  \text{quadrilateral FSHB}\sim\text{quadrilateral KTWJ }

Step-by-step explanation:

To polygons are said to be similar if all the corresponding angles of given polygons are equal.

In the given figure, it can be seen that in quadrilateral FSHB and quadrilateral KTWJ all the corresponding angles are equal.

∠F=∠K

∠S=∠T

∠H=∠W

∠B=∠J

Therefore, The given polygons are similar.

Hence, \text{quadrilateral FSHB}\sim\text{quadrilateral KTWJ }

Mariulka [41]3 years ago
3 0

Answer:

I GOT THE ANSWER OMG IT IS EASY THE ANSWER IS:

do your own homework...JUST KIDDING

it is KTWJ

Step-by-step explanation:

My teacher explained it to me, you have to match up the letters

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352 is the answer

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Consider a sequence defined by the recursive rule f(1) = 15; f(n)=f(n - 1) - 6 for n 2. Choose True or
Shkiper50 [21]

Answer:

The second term of the sequence is 8  False ⇒ B

The third term of the sequence is 3  True ⇒ A

The fourth term of the sequence is -3  True ⇒ A

Step-by-step explanation:

The form of the recursive rule is:

f(1) = first term; f(n) = f(n - 1) + d, where

  • f(1) is the first term
  • f(n) is the nth term
  • f(n - 1) is the term before the nth term
  • d is the common difference

∵ f(1) = 15, f(n) = f(n - 1) - 6 for n ≥ 2

∴ The first term = 15

∴ d = -6

let us find the 2nd, 3rd, and 4th terms

∵ n = 2

∴ f(2) = f(1) - 6

∵ f(1) = 15

∴ f(2) = 15 - 6 = 9

∴ The second term is 9

∴ The second term of the sequence is 8  False

∵ n = 3

∴ f(3) = f(2) - 6

∵ f(2) = 9

∴ f(3) = 9 - 6 = 3

∴ The third term is 3

∴ The third term of the sequence is 3 True

∵ n = 4

∴ f(4) = f(3) - 6

∵ f(3) = 3

∴ f(4) = 3 - 6 = -3

∴ The fourth term is -3

∴ The fourth term of the sequence is -3 True

5 0
3 years ago
NEED HELP ASAP PLEASE !!
Alexxandr [17]

Answer:

A, C, E

Step-by-step explanation:

The square root of 10 is approximately 3.16, which is greater than pi which is equal to about 3.14, which shows that C is correct as well. The square root of 11 is 3.31, and the square root of 5 added to the square root of 6 is equal to about 3.69, which is greater than the square root of 11.

6 0
3 years ago
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